This question provides us –
- Weight of
is = 47 g - Volume, V = 375 mL
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- Molar Mass of
–
<u>Using formula</u> –
- Henceforth, Molarity of the solution is = 1.7M
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Answer:
I didn't do the observation so I can't help sorry
13.8 moles of carbon = 12 g/mol*13.8 or 165.6 grams
165.6 grams/ 2.26 g/mL = 73.27434 or 73.3 mL
I hope this helps!!!!
The balanced equation for reaction of solid cesium with liquid water
= 2Cs + 2H2O → 2CsOH + H2
cesium react with liquid water to produce cesium hydroxide and hydrogen gas
that is 2 moles of Cs react 2 moles of H2O to form 2 moles CsOH and 1 of hydrogen gas
The rate constant for 1st order reaction is
K = (2.303 /t) log (A0 /A)
Where, k is rate constant
t is time in sec
A0 is initial concentration
(6.82 * 10-3) * 240 = log (0.02 /A)
1.63 = log (0.02 /A)
-1.69 – log A = 1.63
Log A = - 0.069
A = 0.82
Hence, 0.82 mol of A remain after 4 minutes.
