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Thepotemich [5.8K]
3 years ago
8

PLS HELP ME ASAP GIVING BRAINLIEST

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

statement

m<abc = m<ghl

reason

transitive property

Step-by-step explanation:

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HELP PLEASE. <br> Area= <br><br> If there is no value under the square root enter a 1.
natali 33 [55]

10^2+16^2=100+256=356^2

The first box should be 2 and the second should be 356

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If three X equal to 216 then find the value of 3 X - 2 ​
lesya [120]

3X-2

=216-2

= 214

214 is the answer...

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Suppose that 4% of all adults suffer from diabetes and that 31% of all adults are obese. Suppose also that 2% of all adults both
den301095 [7]

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I don't see a question. if you comment it on this answer I can try to help

7 0
3 years ago
ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe
xxMikexx [17]

Answer:

654.16-2.02\frac{165.23}{\sqrt{42}}=602.66    

654.16+2.02\frac{165.23}{\sqrt{42}}=705.66    

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=654.16 represent the sample mean

\mu population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=42-1=41

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that t_{\alpha/2}=2.02

Now we have everything in order to replace into formula (1):

654.16-2.02\frac{165.23}{\sqrt{42}}=602.66    

654.16+2.02\frac{165.23}{\sqrt{42}}=705.66    

So on this case the 95% confidence interval would be given by (602.66;705.66)    

7 0
3 years ago
In a candy box, there are 5 times as many candies with nuts as candies without nuts. There are 30 candies in the box. How many c
Luden [163]

Answer:

90

Step-by-step explanation:

because there are 5 time as many candies with nuts as candies without nuts and there is 18 so it will be 18×5=90

6 0
3 years ago
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