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3 years ago

Identify the base in this acid-base reaction:

Chemistry

2 answers:

ivanzaharov [21]3 years ago

7 0

Answer:

B. Mg(OH)2

Explanation:

The other guy explained it, I just shortened it.

kicyunya [14]3 years ago

6 0

<u>Answer:</u> In the given acid-base reaction, the base is $Mg(OH)_2$

<u>Explanation:</u>

Acids are defined as the chemical species which donate hydrogen ions when dissolved in water.

$HA(aq.)\rightarrow H^+(aq.)+A^-(aq.)$

Bases are defined as the chemical species which donate hydroxide ions when dissolved in water.

$BOH(aq.)\rightarrow B^+(aq.)+OH^-(aq.)$

The given chemical equation follows:

$2HC_2H_3O_2+Mg(OH)_2\rightarrow Mg(C_2H_3O_2)_2+2H_2O$

Here, magnesium hydroxide is acting as base because it dissociates into magnesium ions and hydroxide ions when dissolved in water.

The chemical equation for the ionization of magnesium hydroxide follows:

$Mg(OH)_2\rightarrow Mg^{2+}+2OH^-$

Hence, in the given acid-base reaction, the base is $Mg(OH)_2$

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Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re

borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

A + B ⇄ C

where;

numbers of moles = 0.386 mol C (g)

Volume = 7.29 L

Molar concentration of C = $\frac{0.386}{7.29}$

= 0.053 M

A + B ⇄ C

Initial 0 0 0.530

Change +x +x - x

Equilibrium x x (0.0530 - x)

$K = \frac{[C]}{[A][B]}$

where

K is given as ; 78.2 atm-1.

So, we have:

$78.2=\frac{[0.0530-x]}{[x][x]}$

$78.2= \frac{(0.0530-x)}{(x^2)}$

$78.2x^2= 0.0530-x$

$78.2x^2+x-0.0530=0$

Using quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where; a = 78.2 ; b = 1 ; c= - 0.0530

= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

= $\frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$ or $\frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$

= 0.0204 or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

= 0.0530 - 0.0204

= 0.0326

Total number of moles at equilibrium = 0.0204 + 0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

$V = \frac{nRT}{P}$

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K (fixed constant temperature )

V (volume) = ???

$V=\frac{(0.0734*0.0821*273.15)}{(1.00)}$

V = 1.64604

V ≅ 1.65 L

3 0

3 years ago

If you start with 14.0 grams of diatomic nitrogen (N2) how many grams of diatomic hydrogen (H2) will react with it?

irinina [24]

Answer:

I just need points

Explanation:

whegehhwjwjwhehebebejeuhebehejejbebe

7 0

3 years ago

Which of the following results in an increase in the entropy? (4 points)

Dima020 [189]

Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

<h3>What is Entropy ?</h3>

Measurement of randomness of a system is called entropy. It is an extensive property. It is a state function. Unit of entropy is JK⁻¹ mol⁻¹.

Now lets check all options one by one

Option (A): Freezing water

Freezing water decreases the entropy because here second law of thermodynamics does not violate.

So it is incorrect option

Option (B): Cooling water

Cooling water does not increases entropy because entropy increases when solid melts to give liquid.

So it is incorrect option

Option (C): Condensing water vapour

In Condensing water vapour the temperature of liquid phase decreases and thus kinetic energy decreases. The randomness will decrease and hence entropy will also decrease.

So it is incorrect option.

Option (D): Dissolving sugar in solute

In dissolving sugar in solute the solid dissociates to ions and the randomness will increase and hence entropy will also increase.

So it is correct option

Thus from the above conclusion we can say that Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

Learn more about the Entropy here: brainly.com/question/1477087

#SPJ1

6 0

2 years ago

What is the standard reduction potential, E, for the half-reaction Al3+ (aq)

olchik [2.2K]

Answer:

E° = -1.66 V

Explanation:

The standard reduction potential is also known as the standard electrode potentials and it tries to find the probability that an element will be reduced or undergo reduction.

From activation series online showing the standard reduction potentials for half cells, the standard reduction potential of Al3+ (aq) + 3e- -> Al(s) is;

E° = -1.66 V

5 0

3 years ago

Short Question: What is Hydropower?

Brilliant_brown [7]

The use of flowing water to power a turbine to produce electrical energy

3 0

3 years ago

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