Let m1 and m2 be the two masses, whereby m1 is the one that stops upon collision (assuming an elastic collision). We use the conservation of the momentum for this situation, namely the total momentum of the two moving masses is conserved and equal the momentum of the mass2 after the collision:
From this we can determine the resulting velocity:
Which answers the question for general values of m1, m2, v1, and v2.
For instance, if m1=m2, and v1=v2=1 m/s then the resulting velocity of the mass2 would be sqrt(2) m/s in the direction of 45 degrees from its original path.
Explanation:
It is given that,
Wavelength of red light,
Power of the laser,
(a) The energy carried by each photon is given by :
(b) Let n is the number of photons emitted by the laser per second. It can be calculated as :
Hence, this is the required solution.
Answer: The distance traveled by the car once around the racetrack = 100 meters.
Explanation:
Given: The length of the track = 100 meters
- The distance is defined as the actual measurement of the path traveled by a body or an object.
Then, the distance traveled by the car around the racetrack = Length of the track = 100 meters.
Hence, the distance traveled by the car once around the racetrack = 100 meters
Answer:0.4 m
Explanation:
Given
Maximum displacement A=0.49
The sum of kinetic and elastic potential energy is
where k=spring constant
U+K.E.=
when K.E.=U/2
K.E.=kinetic energy
U=Elastic potential Energy
To solve this problem, it is necessary to apply the concepts related to the work done by a body when a certain distance is displaced and the conservation of energy when it is consumed in kinetic and potential energy mode in the final and initial state. The energy conservation equation is given by:
Where,
KE = Kinetic Energy (Initial and Final)
PE = Potential Energy (Initial and Final)
And the other hand we have the Work energy theorem given by
Where
W= Work
F = Force
D = displacement,
PART A) Using the conservation of momentum we can find the speed, so
The height at the end is 0m. Then replacing our values
Deleting the mass in both sides,
Re-arrange for find
PART B) Applying the previous Energy Theorem,
Solving for d