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Mazyrski [523]
3 years ago
8

find the potential energy of an aircraft weighing 10000 bs at 5000 ft true altitude and 125 kts true air speed

Physics
1 answer:
Cloud [144]3 years ago
6 0

Answer:

U=5*10^7ft.Ib

Explanation:

From the question we are told that

Weight  W= 10000bs

Altitude H=5000ft

Speed    V=125kts\\1kts=0.514m/s\\V=125*0.514=>64.25m/s

Generally the equation for Potential energy ids mathematically given as

Potential\ Energy\ U=mgh

U=Wh

U=10000*5000

U=5*10^7ft.Ib

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If a typical smelt weighs 225 g, what is the total mass of pcbs in a smelt in the great lakes? If a typical smelt weighs 225 g,
photoshop1234 [79]

Answer;

= 2.34 x 10^-4 g pcbs

Explanation;

-A typical smelt has 1.04 ppm of PCB is great lakes.

Therefore;

The amount of PCB in a smelt in great leak can be calculated by multiplying the mass of smelt by the pcbs present in a smelt

= 225 g * ( 1.04/100000)

= 2.34 x10^-4 g pcbs

7 0
3 years ago
g Two cars, car 1 and car 2 are traveling in opposite directions, car 1 with a magnitude of velocity v1=13.0 m/s and car 2 v2= 7
bogdanovich [222]

Answer:

When they are approaching each other

    f_a = 2228.7 \  Hz

When they are passing  each other

    f_a = 2100Hz

 When they are retreating  from each other

     f_a =  1980.7 Hz

Explanation:

From the question we are told that

     The velocity of car one is  v_1 = 13.0 m/s

      The velocity of car two is  v_2 = 7.22 m/s

     The frequency of sound from car one is  f_e = 2.10 kHz

Generally the speed of sound at normal temperature is  v = 343 m/s

  Now as the cars move relative to each other doppler effect is created and this  can be represented  mathematically  as

              f_a = f_o [\frac{v \pm v_o}{v \pm v_s} ]

Where v_s is the velocity of the source of sound

            v_o is the velocity of the observer of the sound

            f_o is the actual frequence

             f_a  is the apparent frequency

Considering the case when they are approaching each other

        f_a = f_o [\frac{v +  v_o}{v -  v_s} ]

          v_o = v_2  

         v_s = v_1

         f_o = f_e

Substituting value

            f_a = 2100  [\frac{343 +  7.22}{ 343  -  13} ]

              f_a = 2228.7 \  Hz

Considering the case when they are passing  each other    

At that instant

                  v_o = v_s = 0m/s

                   f_o = f_e

               f_a = f_o [\frac{v }{v } ]

              f_a = f_o

Substituting value

             f_a = 2100Hz

Considering the case when they are retreating  from each other    

                f_a = f_o [\frac{v -  v_o}{v +   v_s} ]

          v_o = v_2  

         v_s = v_1

         f_o = f_e      

Substituting value

         f_a = 2100  [\frac{343 -  7.22}{343 +   13} ]    

          f_a =  1980.7 Hz    

7 0
3 years ago
What is the voltage in a circuit that has a current of 10.0 amps and a resistance of 28.5 ohms?
patriot [66]
<span>Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR.

V = 10.0 A (28.5 ohms) = 285 V </span>
5 0
3 years ago
Read 2 more answers
A man has a mass of 110 kg. What is his weight?<br> A. 110N<br> B. 1325 N<br> C. 559 N<br> D. 1078 N
Slav-nsk [51]

Answer:

Option D

Explanation:

<u><em>Given:</em></u>

Mass = m = 110 kg

Acceleration due to gravity = g = 9.8 m/s

<u><em>Required:</em></u>

Weight = W = ?

<u><em>Formula</em></u>

W = mg

<u><em>Solution:</em></u>

W = (110)(9.8)

W = 1078 N

7 0
3 years ago
A child rides her bike at a rate of 12.0 km/hr down the street. A squirrel suddenly runs in front of her so she applies the brak
Sedbober [7]
By v = u - at 
<span>=>8 = 12 - a x 0.25 </span>
<span>=>a = 4/0.25 km/hr/sec </span>
<span>=>a = 16km/hr/sec

I hope this helped!</span>
3 0
3 years ago
Read 2 more answers
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