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Mazyrski [523]
3 years ago
8

find the potential energy of an aircraft weighing 10000 bs at 5000 ft true altitude and 125 kts true air speed

Physics
1 answer:
Cloud [144]3 years ago
6 0

Answer:

U=5*10^7ft.Ib

Explanation:

From the question we are told that

Weight  W= 10000bs

Altitude H=5000ft

Speed    V=125kts\\1kts=0.514m/s\\V=125*0.514=>64.25m/s

Generally the equation for Potential energy ids mathematically given as

Potential\ Energy\ U=mgh

U=Wh

U=10000*5000

U=5*10^7ft.Ib

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A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
PilotLPTM [1.2K]

Answer:

859.07 N

Explanation:

u = Initial velocity = 1.9 m/s

v = Final velocity

s = Displacement = 0.165 m

a = Acceleration

m = Mass = 890 kg

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-1.9^2}{2\times 0.165}\\\Rightarrow a=-10.93\ m/s^2

Force

F=ma\\\Rightarrow F=870\times -10.93\\\Rightarrow F=859.07\ N

The magnitude of the average force on the bumper is 859.07 N

4 0
3 years ago
1. A 3.5 kg object experiences an acceleration of 0.5 m/s2. What net force does the object experience
Leviafan [203]

Answer:

<h2>1.75 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.5 × 0.5 = 1.75

We have the final answer as

<h3>1.75 N</h3>

Hope this helps you

7 0
3 years ago
If you drop a bouncing ball from a height of 40 centimeters, explain why it can only bounce back up to a height of less than 40
iren2701 [21]

Answer:

Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height

Explanation:

As we know that initially ball is held at height h = 40 cm

So here we can say that kinetic energy of the ball is zero and potential energy is given as

U = mgH

now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies

So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height

While if we assume that there is no energy loss during collision then in that case ball will reach to same height again

8 0
3 years ago
Anna is sitting in a moving cart and throws a ball straight up. Theoretically, the ball should land in the cart, but it lands on
anastassius [24]

The guys before me was almost right. But instead of it being vertical it is horizontal.

8 0
3 years ago
Read 2 more answers
A Carnot air conditioner takes energy from the thermal energy of a room at 63°F and transfers it as heat to the outdoors, which
vodomira [7]

Answer:

For the Carnot air conditioner working as a heat pump between 63 and 100°F , It would transfer 3.125 Joules of heat for each Joule of electric energy supplied.

Explanation:

The process described corresponds to a Carnot Heat Pump. A heat pump is a devices that moves heat from a low temperature source to a relative high temperature destination. <em>To accomplish this it requires to supply external work</em>.

For any heat pump, the coefficient of performance is a relationship between the heat that is moving to the work that is required to spend doing it<em>.</em>

For a Carnot Heat pump, its coefficient of performance is defined as:

COP_{HP}=\frac{T_H}{T_H-T_L} Where:

  • T is the temperature of each heat deposit.
  • The subscript H refers to the high temperature sink(in this case the outdoors at 100°F)
  • The subscript L refers to the low temperature source (the room at 63°F)

Then, for this Carnot heat pump:

COP_{HP}=\frac{T_H}{T_H-T_L}=\frac{100°F}{100°F-63°F}=3.125

So for each 3.125 Joules of heat to moved is is required to supply 1 Joule of work.

3 0
3 years ago
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