The distance from the earthquake`s focus.
Answer:
31.92 h
Explanation:
We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:
Original amount (N₀) = 1
Amount remaining (N) = ⅛
Number of half-lives (n) =?
N = 1/2ⁿ × N₀
⅛ = 1/2ⁿ × 1
Cross multiply
2ⁿ = 8
Express 8 in index form with 2 as the base.
2ⁿ = 2³
n = 3
Thus, 3 half-lives has elapsed.
Finally, we shall determine the time. This can be obtained as follow:
Half-life (t½) = 10.64 h
Number of half-lives (n) = 3
Time (t) =?
n = t / t½
3 = t / 10.64
Cross multiply
t = 3 × 10.64
t = 31.92 h
Therefore, it will take 31.92 h for lead-212 to decay to one-eighth its original strength.
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Answer:
work done = 117 kJ
Explanation:
given data
mass m = 3 kg
constant pressure P = 200 kPa
temperature T = 200°C
solution
we know that work done by steam is express as
work done = pressure × ΔVolume ....................1
and here ΔVolume = final volume - initial volume
we use here steam table and get at pressure 200 kPa
final specific volume = 1.08052 m³/kg
and
initial specific volume = 0.885735 m³/kg
so here
ΔV = 3 × (1.08052 - 0.885735)
ΔV = 0.584 m³
so put value in equation 1 we get
work done by steam = 200 × 0.584
work done = 117 kJ
Answer:
When we are outside on a sunny day, we can see how our shadows change throughout the day. The Sun's position in the sky affects the length of the shadow. When the Sun is low on the horizon, the shadows are long. Due to the Earth's rotation, our view of the Sun changes throughout the day.
I hope this helps u! :D