A motor pulls an 800 kg roller coaster train to the top of a 70 m hill. What is the change in the potential energy of the cars?

Physics

1 answer:

Angelina_Jolie [31]3 years ago

5 0

Answer:

548800J

Explanation:

Given parameters:

Mass of roller coaster = 800kg

Height of hill = 70m

Unknown:

Change in potential energy = ?

Solution:

The change in potential energy is the difference between the potential energy at the bottom and at the top.

Potential energy at the bottom is 0J

So;

Change in potential energy = mgh - 0

m is the mass, g is the acceleration, h is the height

Change in potential energy = 800 x 9.8 x 70 = 548800J

You might be interested in

Kilo- - 1,000<br>deka- - 10<br><br>How much larger is a kilo- than a deka-?

Ilya [14]

$lets's \ take \ an \ example \ one \ gram: \\ \\ 0,001kg \\ \\ 0,01hg \\ \\ 0,1dag \\ \\ \boxed{1g} \\ \\ 10dg \\ \\ 100cg \\ \\ 1000mg \\ \\ the \ units \ are \ rising \ and \ decreasing \ from \ 10 \ to \ 10 \ results \ \\ \\ a \ kilogram \ is \ 100 \ times \ larger \ than \ a \ dekagram$

6 0

3 years ago

Helphpphphphpphphphpphphpph

adell [148]

Airplane with nose up: The plane's speed through the air is the square root of (80 m/s squared) plus (120 m/s squared. The whole picture is a right triangle, and the plane's speed is the hypotenuse. The angle is the angle whose tangent is (80/120). You can get it from a calculator, a book, a slide rule, or online from the site that rhymes with floogle. The man pulling the load is also a right triangle. The horizontal component is (hypotenuse) times (cosine of the angle). The vertical component is (hypotenuse) times (sine of the same angle). Fill in what you know, look up the sin and cos of 25 degrees and write those in too, and then you can solve for what you have to find.

7 0

3 years ago

During the launch from a board, a diver's angular speed about her center of mass changes from zero to 8.10 rad/s in 240 ms. Her

Artemon [7]

Answer:

Part a)

$\alpha = 33.75 rad/s^2$