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4 years ago

Rosa uses the formula (vi¡cosθ)tΔ to do a calculation. Which value is Rosa most likely trying to find?

1 answer:

4 0

To break this problem down, let's start with what we know. The equation given finds one component of the velocity and multiplies it by the change in time. This will not find the acceleration that the first two answers say it will, meaning that the answer isn't A or B.

That leaves us with the final two answers, C and D. If the projectile was launched horizontally and we were trying to find the horizontal displacement, we wouldn't need to use cosθ to find the horizontal velocity, meaning that our answer is most likely C) <span>the horizontal displacement of a projectile launched at an angle!</span><span />

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Assume that a 15-kg ball moving at 8 m/s strikes a wall perpendicularly and rebounds elastically at the same speed. What is the

Aleks [24]

I think u should follow the formulae F=MA. So I think the answer is 120N

5 0

3 years ago

The Hall effect can be used to calculate the charge-carrier number density in a conductor. If a conductor carrying a current of

goldfiish [28.3K]

Answer:

$6.6*10^{27}e/m^3$

Explanation:

When we are dealing with Hall voltage, it is necessary to have the values of the current, the magnetic field, the length, the area and the number of carriers at hand. The Hall voltage equation is given by, $V_h = \frac{iB}{neL}$

Where,

i= current

B= Magnetic field

L = Length

n = number of charge carriers

e= charge of a electron

We need replace and solve for n,

$n= \frac{iB}{V_h e L}$

$n= \frac{2*1.2}{4.5*10^{-6}*5^10^{-3}*1.6*10^{-19}}$

$n= 6.6*10^{27}electron.m^{-3}$

Therefore the density of charge carrier is $6.6*10^{27}e/m^3$

5 0

4 years ago

Momentum is a scalar quantity.<br>True or false

Rudiy27

The answer is false

5 0

3 years ago

Read 2 more answers

If the torque required to loosen a nut that holds a wheel on a car has a magnitude of 55 n·m, what force must be exerted at the

erastova [34]

Either 175 N or 157 N depending upon how the value of 48Â° was measured from.
You didn't mention if the angle of 48Â° is from the lug wrench itself, or if it's from the normal to the lug wrench. So I'll solve for both cases and you'll need to select the desired answer.
Since we need a torque of 55 NÂ·m to loosen the nut and our lug wrench is 0.47 m long, that means that we need 55 NÂ·m / 0.47 m = 117 N of usefully applied force in order to loosen the nut. This figure will be used for both possible angles.
Ideally, the force will have a 0Â° degree difference from the normal and 100% of the force will be usefully applied. Any value greater than 0Â° will have the exerted force reduced by the cosine of the angle from the normal. Hence the term "cosine loss".
If the angle of 48Â° is from the normal to the lug wrench, the usefully applied power will be:
U = F*cos(48)
where
U = Useful force
F = Force applied
So solving for F and calculating gives:
U = F*cos(48)
U/cos(48) = F
117 N/0.669130606 = F
174.8537563 N = F
So 175 Newtons of force is required in this situation.
If the 48Â° is from the lug wrench itself, that means that the force is 90Â° - 48Â° = 42Â° from the normal. So doing the calculation again (this time from where we started plugging in values) we get
U/cos(42) = F
117/0.743144825 = F
157.4390294 = F
Or 157 Newtons is required for this case.

6 0

3 years ago

HELP I WILL GIVE YOU ALL MY POINTS OR ANYTHING JUST HELP ME PLS

tiny-mole [99]

Answer: B, they can land themselves now

Explanation:

6 0

3 years ago