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2 years ago

Kilo- - 1,000deka- - 10How much larger is a kilo- than a deka-?

1 answer:

6 0

$lets's \ take \ an \ example \ one \ gram: \\ \\ 0,001kg \\ \\ 0,01hg \\ \\ 0,1dag \\ \\ \boxed{1g} \\ \\ 10dg \\ \\ 100cg \\ \\ 1000mg \\ \\ the \ units \ are \ rising \ and \ decreasing \ from \ 10 \ to \ 10 \ results \ \\ \\ a \ kilogram \ is \ 100 \ times \ larger \ than \ a \ dekagram$

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Many scientists accept a theory about the origin of the universe, called the big bang theory. describe at least one piece of sci

alexandr402 [8]

Red shift is one piece of observational evidence which supports the big bang theory. The fact that galaxies are moving away from us means that the universe was once much smaller, supporting the big bang theory which states that all the matter in the universe once occupied a single point with infinite density.

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2 years ago

Nature selects organisms with specific ______to survive and reproduce

Effectus [21]

Answer:

Nature selects organisms with specific heritable traits to survive and reproduce

Explanation:

The Evolution Theory by natural selection dictates that organisms with specific inherited characteristics have better survival chances in the new environment.

Inheriting positive traits such as resistance to a certain disease will improve the survival chances of the organism to enable it reproduce and pass that gene to the next generation.

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3 years ago

Read 2 more answers

(a) A space vehicle is launched vertically upward from the Earth's surface with an initial speed of vi that is comparable to but

ad-work [718]

Energy Conservation Theory,

$(k+v)_i=(k+v)_f \quad \text { (No air resistone)}\\$

$\frac{1}{2} m v_i^2-\frac{G m M_\epsilon}{R_\epsilon}=0-\frac{G m M_\epsilon}{R_\epsilon+h}$

$v_{e x^2}{ }^2-v_i^2=\frac{v_{e^2 R_t} R_t}{R_t t h}\\&\frac{1}{v_{B C^2-v_1^2}^2}=\frac{R_E+h}{v_{e^2 R_E} R_E}\\\\\\h=\frac{R_E V_1^2}{v_{\text {esc }}^2-v_1^{\beta^2}}$

<h3>What is law of energy conservation?</h3>

The principle of energy conservation states that energy is neither created nor destroyed. It may change from one sort to another. Just like the mass conservation rule, the legitimacy of the preservation of energy depends on experimental perceptions; hence, it is an experimental law. The law of preservation of energy, too known as the primary law of thermodynamics

To learn more about Energy Conservation Theory, visit;

brainly.com/question/8004680

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7 0

1 year ago

Dejamos caer un objeto desde lo alto de una torre y medimos el tiempo que tarda en llegar al suelo que resulta ser de 0,02 minut

Harman [31]

Answer: a) 11.76 m/s b) 7.056 m

Explanation:

The described situation is as follows:

An object is dropped from the top of a tower and when measuring the time it takes to reach the ground that turns out to be 0.02 minutes.

This situation is related to free fall, this also means we have constant acceleration, hence the equations we will use are:

$V_{f}=V_{o}+at$ (1)

${V_{f}}^{2}={V_{o}}^{2}+2ad$ (2)

Where:

$V_{f}$ Is the final velocity of the object

$V_{o}=0$ Is the initial velocity of the object (it was dropped)

$a=9.8 m/s^{2}$ is the acceleration due gravity

$d$ is the height of the tower

$t=0.02min=1.2 s$ is the time it takes to the object to reach the ground

b) Begining with (1):

$V_{f}=0+at$ (3)

$V_{f}=at=(9.8 m/s^{2})(1.2 s)$ (4)

$V_{f}=11.76 m/s$ (5) This is the final velocity of the object

a) Substituting (5) in (2):

$(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d$ (6)

Clearing $d$ :

$d=\frac{(11.76 m/s)^{2}}{2(9.8 m/s^{2})}$ (7)

$d=7.056 m$ (8) This is the height of the tower

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3 years ago

The energy of an object can be converted to heat due to the friction of the car on the hill. The difference between the potentia

MAVERICK [17]

Answer:

Energy Lost for group A's car = 0.687 J

Energy Lost for group B's car = 0.55 J

Explanation:

The exact question is as follows :

Given - The energy of an object can be converted to heat due to the friction of the car on the hill. The difference between the potential energy of the car and its kinetic energy at the bottom of the hill equals the energy lost due to friction.

To find - How much energy is lost due to heat for group A's car ?

How much for Group B's car ?

Solution -

We know that,

GPE = 1 Joule (Potential Energy)

Now,

For Group A -

Energy Lost = GPE - KE

= 1 J - 0.313 J

= 0.687 J

So,

Energy Lost for group A's car = 0.687 J

Now,

For Group B -

Energy Lost = GPE - KE

= 1 J - 0.45 J

= 0.55 J

So,

Energy Lost for group B's car = 0.55 J

8 0

3 years ago