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3 years ago

After striking both mirrors, at what angle relative to the incoming ray does the outgoing ray emerge?

1 answer:

4 0

The appropriate response is Zero degrees. The beam will leave the two mirrors along a way parallel to the one it came in on. This is the guideline of the corner reflector, which is frequently utilized as a radar target. Take note of that the corner reflector utilizes three reflecting surfaces (that are set up at 90o from each other) rather than the two like are being utilized here. Wikipedia has a truly awesome drawing that shows this two-dimentional issue pleasantly. A moment connection is given to the article on the corner reflector and the 3-D angles.

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When the time of day for a certain ship at sea is 12 noon, the time of day at the prime meridian (0 longitude0 is 5 pm. what is

azamat

A). The sun is highest in London, but will not pass the ship
for another 5 hours.

Since the sun moves from east to west, the ship must be
5 hours west of Greenwich.

Each hour of sun motion is 15° of longitude.
The ship's longitude is (5 x 15°) = 75° West.

The ship may be sailing down Columbia Boulevard
in Maple Shade, New Jersey.

B). The latitude at Buffalo's City Hall is 42.887° North.

Polaris is always within about 2/3 of a degree of that angle
above the northern horizon, when viewed from City Hall.

Choice 2) is the most appropriate.

4 0

4 years ago

2.) The speed of light in a vacuum is c = 300,000 km / s. The light of Sol takes 8 minutes and 19 seconds to reach Earth. Calcul

Vinvika [58]

Answer:

149,700,000 km (= 1.50 x 10⁸ km)

Explanation:

Given,

Speed of light, c = 300,000 km/s

Time Taken = 8 min 19 s = 499 seconds

Recall, Distance = Speed x Time

= 300,000 km/s x 499 s

= 149,700,000 km

= 1.50 x 10⁸ km

3 0

3 years ago

Read 2 more answers

What happens is a series circuit when you increase the number of bulbs?

Volgvan

The bulbs will produce lesser light than their capacity, In short they will be dimmer because the the energy will get divided in the number of bulbs.

5 0

3 years ago

An automatic shotgun has a mass of 10 kg. It fires 30 g bullets at the rate of 6 bullets per second with a speed of 400 m/s. Wha

igomit [66]

Answer:72 N

Explanation: thats whats right

6 0

3 years ago

A ball rolls off a desk at a speed of 2 m/s and lands 0.50 seconds later.

Hoochie [10]

Answer:

(a) The ball lands <u>1 m</u> ahead of the desk's base.

(b) The height of the desk is <u>1.225 m.</u>

Explanation:

Given:

Initial velocity of the ball is, $u_{0}=2\ m/s$

Time of flight of the ball is, $t=0.50\ s$

(a)

Let the ball fall at a distance of $x$ from the base of the desk and let the height of the desk be $y$ .

The given motion of the ball is a projectile motion that can be divided into 2 mutually perpendicular directions.

Now, considering only the horizontal motion of the ball. The ball not under the influence of any force in the horizontal direction.

Therefore, the distance covered by the ball horizontally is given as:

$x=v_0\times t\\x=2\times 0.50=1\ m$

So, the ball lands 1 m ahead of the desk's base.

(b)

Now, consider only the vertical motion of the ball. The ball is under the influence of gravity.

So, vertical distance can be obtained using Newton's equations of motion.

We use the following equation of motion:

$y-y_0=u_{oy}t+\frac{1}{2}gt^2$

Where,

$y_{0}\rightarrow \textrm{initial vertical position of ball}\\u_{oy}\rightarrow \textrm{initial vertical velocity}\\g\rightarrow \textrm{acceleration due to gravity}\\y\rightarrow \textrm{final position of ball vertically}$

Here, as the ball leaves the desk horizontally, initial velocity is only in the horizontal direction and doesn't have any component in the vertical direction. So, $u_{oy}=0\ m/s$

Plug in $y_0=h,y=0,g=-9.8,u_{oy}=0,t=0.5$ . Solve for $h$ .

$0-h=0+\frac{1}{2}(-9.8)(0.5)^2\\-h=-4.9\times 0.25\\h=1.225\ m$

Therefore, the height of the desk is 1.225 m.

6 0

3 years ago