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cricket20 [7]
1 year ago
9

An energy source will supply a constant current into the load if its internal resistance is.

Physics
1 answer:
Illusion [34]1 year ago
4 0

Answer:

If its internal resistance is zero or remains constant.

Explanation:

  • Considering the attached figure it is possible to be written an expression for the current that flows through the load connected to a source of voltage as follows.

                                                 \begin{aligned}\ \small i&=\small \frac{E}{R+r}\end{aligned}

  • Here, E,\,R,\,r represent the voltage of the energy source, the load resistance and the internal resistance of the source respectively
  • The denominator of the fraction is subject to change due to r being the possible parameter that is variable.
  • Therefore, the current can be fixed at \bold{r =0} or \bold{r = k}, k = constant.
  • In such a case the current would appear to be in either form as follows,

                                \begin{aligned}i = \frac{V}{R} \qqud \qquad \text{or}\qquad i = \frac{V}{R+k}\end{aligned}

  • Once either of the above condition is held the current  = constant.

#SPJ4

                                                 

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Answer:

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Explanation:

From first Law of Thermodynamics, we know that:

ΔQ = ΔU + W

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Therefore,

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Now, the work done in a constant pressure condition is given by:

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W = P(Vf - Vi)

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Therefore,

155 J = (50662.5 Pa)(0.058 m³ - Vi)

Vi = 0.058 m³ - 155 J/50662.5 Pa

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3 years ago
A student is swimming south applying a force of 256 N. The water exerts a westward force of 104 N. If the student has a mass of
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Answer:

a=2.9\ m/sec^2

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<u>Net Forces and Acceleration</u>

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\vec F_r=m\vec a

According to the information given in the question, two forces are acting on the swimming student: One of 256 N pointing to the south and other to the west of 104 N. Since those forces are not aligned, we must add them like vectors as shown in the figure below.

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\displaystyle a=\frac{F_r}{m}

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\boxed{a=2.9\ m/sec^2}

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