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docker41 [41]
3 years ago
11

Suppose the coefficient of static friction between the road and the tires on a car is 0.638 and the car has no negative lift. Wh

at speed will put the car on the verge of sliding as it rounds a level curve of 25.5 m radius?
Physics
1 answer:
larisa [96]3 years ago
4 0

Answer:

12.6332454263 m/s

Explanation:

m = Mass of car

v = Velocity of the car

\mu = Coefficient of static friction = 0.638

g = Acceleration due to gravity = 9.81 m/s²

r = Radius of turn = 25.5 m

When the car is on the verge of sliding we have the force equation

\dfrac{mv^2}{r}=\mu mg\\\Rightarrow v=\sqrt{\mu gr}\\\Rightarrow v=\sqrt{0.638\times 9.81\times 25.5}\\\Rightarrow v=12.6332454263\ m/s

The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s

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