Answer:
The symbol of isotopes used for blood flow analysis is
<u>Explanation:
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- Isotopes are the substances that exhibit the same atomic number but has a different mass number of an element.
- The atomic number explains the number of protons present in the element and mass number explains the number of neutrons available in the element.
- For blood flow analysis, the isotope element is cerium-141 and it is used in the chemical examination of blood flow particles.
- Symbol used for this isotope is
, where 141 indicates the amount of mass present and 58 indicates the proton number and 83 indicates neutron number present in that element.
- The amount of mass in an atom is calculated by the sum of protons and neutrons present in it. Thus mass of isotope is 141 obtained by the sum of 58 protons and 83 neutrons present in that isotope.
Answer:
Alcohols are usually named by the first procedure and are designated by an -ol suffix, as in ethanol, CH3CH2OH (note that a locator number is unnecessary on a two-carbon chain). On longer chains the location of the hydroxyl group determines chain numbering. For example: (CH3)2C=CHCH(OH)CH3 is 4-methyl-3-penten-2-ol.10
Explanation:
Answer: False
Explanation:
4C2H6 + 7O2 --> 6H2O + 4CO2
8 Carbons on the reactant side, but 4 Carbons on the Product
24 Hydrogens on Reactant, 12 H on product
But Oxygen is balanced, 14 on each side
Answer:
The order of elements by volume-fraction (which is approximately molecular mole-fraction) in the atmosphere is nitrogen (78.1%), oxygen (20.9%), argon (0.96%), followed by (in uncertain order) carbon and hydrogen because water vapor and carbon dioxide, which represent most of these two elements in the air, are variable.
I copied and pasted but I hope this information is helpful :)
Answer:
Explanation:
Chlorine has electronic configuration of 2 , 8 , 7
In n = 3 there are 7 electrons out of which 2 are in s , and 5 are in p . But out of 5 electrons in p , one electron jumps into d orbital . so the electronic configuration becomes as follows
= 7
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These orbitals like sp³d hybridise to form 7 degenerate orbitals out of which 2 orbitals contain electrons in pairs and rest three are singly occupied by electrons.( unpaired electrons )