Question

Given the following balanced equation, determine the rate of reaction with respect to [SO3]. If the rate of O2 loss is 3.56 x 10-3 M/s, what is the rate of formation of SO3?

Answer 1

Answer:

7.12 × 10⁻³ M/s

Explanation:

Step 1: Write the balanced reaction

2 SO₂ + O₂ ⇒ 2 SO₃

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to SO₃ is 1:2.

Step 3: Calculate the rate of formation of SO₃

The rate of loss of O₂ is 3.56 × 10⁻³ mol O₂/L.s. The rate of formation of SO₃ is:

3.56 × 10⁻³ mol O₂/L.s. × 2 mol SO₃/1 mol O₂ = 7.12 × 10⁻³ mol SO₃/L.s