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puteri [66]
3 years ago
10

Brandon has a box 9.5 inches tall, 3.8 inches wide, and 4.2 inches long. How many square inches of wrapping paper does he need t

o wrap the box?
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Answer:

183.92 inch²

Step-by-step explanation:

To find the total amount of wrapping paper needed, you must find the Surface Area of the box.

Surface area of a rectangular prism is: A = 2(<em>wl</em> + <em>hl</em> + <em>hw</em>)

w = width = 3.8

h = height = 9.5

l = length = 4.2

Plug in the corresponding numbers to the corresponding variables.

A = 2(<em>wl</em> + <em>hl </em>+ <em>hw</em>)

A = 2((3.8 * 4.2) + (9.5 * 4.2) + (9.5 * 3.8))

Simplify.

A = 2((15.96) + (39.9) + (36.1))

A = 2(15.96 + 39.9 + 36.1)

A = 2(91.96)

Multiply.

A = 183.92

183.92 inch² is your answer.

~

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3 years ago
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Step-by-step explanation:

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3 years ago
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Travka [436]

Answer:

If the x-6 is all under the sqrt, the last answer is right:

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Step-by-step explanation:

You can look at the equation and or graph to determine the domain of a function. The domain is all the x's that may go into the equation or all the x's on the graph of the function. Inside of a squareroot symbol the number inside there must be positive. While considering the equation, only x's that keep that inside positive can be used.

For sqrt(x-6), x has to be 6 or bigger.

For sqrt(x) - 6, x has to be 0 or bigger.

6 0
2 years ago
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Answer:

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Assuming you're solving for Q, the first step is to multiply the first set of parenthesis by 0.10:

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Now isolate 0.15Q:

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0.15Q = 7.5

Divide 7.5 by 0.15 to solve for Q:

Q = 7.5/0.15 = 50

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