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3 years ago

Help with this please.

Physics

1 answer:

gregori [183]3 years ago

8 0

Rutherford's experiment utilized positively charged alpha particles (He with a +2 charge) which were deflected by the dense inner mass (nucleus). The conclusion that could be formed from this result was that atoms had an inner core which contained most of the mass of an atom and was positively charged.

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3) A school bus traveling at 12 m/s has a momentum of 144,000 kg.m/s.

spin [16.1K]

Answer:

does this have picture so I can solve

6 0

3 years ago

Read 2 more answers

PLEASE HELP! How much heat is absorbed by 57g iron skillet when its temperature rises from 11°c to 30°C?

Amiraneli [1.4K]

mass times specific heat times tem change.

57 x sh x (30-11)

convert to mks and look up sh iron

7 0

3 years ago

Select the correct answer.

Natali [406]

its b hoped i helped

8 0

3 years ago

Read 2 more answers

A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of

balandron [24]

Answer:

The skater covers a distance of 15 m before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

$f=\mu N$

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, $N=mg$

∴ $f=\mu mg=0.490\times 90\times 9.8=432.18\ N$

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

$W=-fd=-432.18d$

Now, change in kinetic energy is given as:

$\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J$

Therefore, from work-energy theorem,

$W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m$

Hence, the skater covers a distance of 15 m before stopping.

7 0

3 years ago

How do gravity assists in rock being transported to a new place

bazaltina [42]

The gravity deposits the rocks using deposition which means it brings it to another place using any type of natural force such as wind rain sleet and snow etc

7 0

3 years ago