The formula of net Force is:F = mawhere m is the mass of the objecta is the acceleration of the object
thus, if we triple the net force applied to the object:
3F = maa = 3F / m
The acceleration is also tripled since the force is directly proportional to the acceleration.
Answer:
481.76 J/mol
133.33 K
Explanation:
= Avogadro's number = ![6.022\times 10^{23}](https://tex.z-dn.net/?f=6.022%5Ctimes%2010%5E%7B23%7D)
Change in enthalpy is given by
![\Delta H=8\times 10^{-22}\times 6.022\times 10^{23}\\\Rightarrow \Delta H=481.76\ J/mol](https://tex.z-dn.net/?f=%5CDelta%20H%3D8%5Ctimes%2010%5E%7B-22%7D%5Ctimes%206.022%5Ctimes%2010%5E%7B23%7D%5C%5C%5CRightarrow%20%5CDelta%20H%3D481.76%5C%20J%2Fmol)
Entropy is given by
![\Delta S=6\times 10^{-24}\times 6.022\times 10^{23}\\\Rightarrow \Delta S=3.6132\ J/mol K](https://tex.z-dn.net/?f=%5CDelta%20S%3D6%5Ctimes%2010%5E%7B-24%7D%5Ctimes%206.022%5Ctimes%2010%5E%7B23%7D%5C%5C%5CRightarrow%20%5CDelta%20S%3D3.6132%5C%20J%2Fmol%20K)
Latent heat of fusion is given by
![L_f=\Delta H\\\Rightarrow L_f=481.76\ J/mol](https://tex.z-dn.net/?f=L_f%3D%5CDelta%20H%5C%5C%5CRightarrow%20L_f%3D481.76%5C%20J%2Fmol)
The latent heat of fusion is 481.76 J/mol
Melting point is given by
![T_m=\dfrac{L_f}{\Delta S}\\\Rightarrow T_m=\dfrac{8\times 10^{-22}\times 6.022\times 10^{23}}{6\times 10^{-24}\times 6.022\times 10^{23}}\\\Rightarrow T_f=133.33\ K](https://tex.z-dn.net/?f=T_m%3D%5Cdfrac%7BL_f%7D%7B%5CDelta%20S%7D%5C%5C%5CRightarrow%20T_m%3D%5Cdfrac%7B8%5Ctimes%2010%5E%7B-22%7D%5Ctimes%206.022%5Ctimes%2010%5E%7B23%7D%7D%7B6%5Ctimes%2010%5E%7B-24%7D%5Ctimes%206.022%5Ctimes%2010%5E%7B23%7D%7D%5C%5C%5CRightarrow%20T_f%3D133.33%5C%20K)
Melting occurs at 133.33 K
Answer:
1. 310 N
2. 310 N
Explanation:
1. Determination of the net force.
Force applied (Fₐ) = 430 N
Force experience (Fₑ) = 120 N
Net force (Fₙ) =?
Fₙ = Fₐ – Fₑ
Fₙ = 430 – 120
Fₙ = 310 N
Hence, the net force acting on the crate is 310 N
2. Determination of the net force.
Force applied (Fₐ) = 375 N
Force of friction (Fբ) = 65 N
Net force (Fₙ) =?
Fₙ = Fₐ – Fբ
Fₙ = 375 – 65
Fₙ = 310 N
Hence, the net force acting on the crate is 310 N.