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NNADVOKAT [17]
3 years ago
7

Water flows upward in a pipe oriented at 30 degrees. The mercury manometer readsh= 12 cm. Bothfluids are at 20â—¦C. What is the

pressure lossp1−p2in the pipe (in Pascals)?

Physics
1 answer:
NISA [10]3 years ago
4 0

Answer:

The pressure difference in the pipe is 2666 Pa.

Explanation:

Given that,

Height = 12 cm

Angle = 30°

We need to calculate the height

Using formula of height

h_{1}=2\tan30

h_{1}=1.154\ m

We need to calculate the pressure difference in the pipe

Using formula of pressure

P_{2}=P_{1}+\rho_{w}h-\rho_{Hg}h-\rho_{w}h_{1}

P_{2}-P_{1}=\rho_{w}h-\rho_{Hg}h-\rho_{w}h_{1}

Where, \rho_{Hg} = density of mercury

\rho_{w} = density of water

Put the value into the formula

P_{2}-P_{1}=(13600-1000)\times12\times10^{-2}+1000\times1.154

P_{2}-P_{1}=2666\ Pa

Hence, The pressure difference in the pipe is 2666 Pa.

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