Question

Water flows upward in a pipe oriented at 30 degrees. The mercury manometer readsh= 12 cm. Bothfluids are at 20◦C. What is the pressure lossp1−p2in the pipe (in Pascals)?

Answer 1

Answer:

The pressure difference in the pipe is 2666 Pa.

Explanation:

Given that,

Height = 12 cm

Angle = 30°

We need to calculate the height

Using formula of height

$h_{1}=2\tan30$

$h_{1}=1.154\ m$

We need to calculate the pressure difference in the pipe

Using formula of pressure

$P_{2}=P_{1}+\rho_{w}h-\rho_{Hg}h-\rho_{w}h_{1}$

$P_{2}-P_{1}=\rho_{w}h-\rho_{Hg}h-\rho_{w}h_{1}$

Where, $\rho_{Hg}$ = density of mercury

$\rho_{w}$ = density of water

Put the value into the formula

$P_{2}-P_{1}=(13600-1000)\times12\times10^{-2}+1000\times1.154$

$P_{2}-P_{1}=2666\ Pa$

Hence, The pressure difference in the pipe is 2666 Pa.