Question

What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 4.5 × 10-4 mm (1.772 × 10-5 in.) and a crack length of 3.5 × 10-2 mm (1.378 × 10-3 in.) when a tensile stress of 180 mpa (26110 psi) is applied?

Answer 1

This problem asks that we compute the magnitude of the maximum stress that exists at the tip of an internal crack
 sigmam=2*(sigma0)(a/(pt))^(1/2)
 sigmam= 2*(180)*(((3.5×10^-2)/(2))/(4.5×10-4))^(1/2)=2245 MPA (325609.7 PSI)