Answer:
The change in gravitational potential energy is -1.80x10⁵ J.
Explanation:
The change in gravitational potential energy is given by:
Where:
"i" is for final and "f" for final
m: is the mass
g: is the gravity = 9.81 m/s²
h: is the height
For the car and the passengers we have:
The minus sign is because when the elevator car and the passengers are up they have a bigger gravitational potential energy than when they are in the ground.
Therefore, the change in gravitational potential energy is -1.80x10⁵ J.
I hope it helps you!
Answer:
Explanation:
We will use the KE equation you wrote here and fill in what we are given:
and isolating the m:
which gives us
m = .50 kg
Answer:
0.012 N
Explanation:
The formula to apply is that adopted from the Ampere law which is;
F= μ* I₁*I₂*l /2πd where
F is force that one conductor exerts on the other.
μ = magnetic permeability of free space = 4π×10⁻⁷ T. m/A
I₁ = current in conductor one=10 A
I₂ = current in conductor two= 10 A
l= length of conductor= 3 m
d= distance between the conductors = 5 mm = 0.005 m
Applying the values in the equation
F= 4π×10⁻⁷ *10*10*3 / 2π*0.005
F= 6 * 10⁻⁵ / 0.005
F=0.012 N
Answer:
Kindly check the explanation section.
Explanation:
For the design we are asked for in this question/problem there is the need for us to calculate or determine the strength in fracture and that of the yield. Also, we need to calculate for the block shear strength.
From the question, we have that the factored load = 500kips. Also, note that the tension splice must not slip.
Also, the shear force are resisted by friction, that is to say shear resistance = 1.13 × Tb × Ns.
Assuming our db = 3/4 inches, then the slip critical resistance to shear service load = 18ksi(refer to AISC manual for the table).
If db = 7/8 inches, then the shear force resistance for n bolt = 10.2kips, n > 49.6.
The yielding strength = 0.9 × Aj × Fhb= 736 kips > 500
The fracture strength = .75 × Ah × Fhb = 309 kips.
The bearing strength of 7/8 inches bolt at the edge hole and other holes = 46 kips and 102 kips.
4 cars = 16 students
? cars = 36 students
let x be the number of cars for 36 students
4 • 36 = 16 • x
144 = 16x
144/16 = x
9 = x
It requires 9 cars for 36 students.
//Hope it helps
