Answer:
" At four he decided to get it over with and started walking to Sandra's house, trudging slowly, as if he were waist-deep in water. "
Explanation:
Answer:
Check the explanation
Explanation:
As we know the reaction of EDTA and 
+ and EDTA and 
+
Let us say that the ratio is 1:1
Therefore, the number of moles of + = molarity * volume
= 0.0400M * 0.011L
= 0.00044 moles
Therefore excess EDTA moles = 0.00044 moles
Given , initial moles of EDTA = 0.0430 M * 0.025 L
= 0.001075
Therefore reacting moles of EDTA with 
= 0.001075 - 0.00044 = 0.000675 moles
Let us say that the ratio between and EDTA is 1:1
Therefore moles of = 0.000675 moles
Molarity = moles / volume
= 0.000675 moles / 0.057 L
= 0.011 M (answer).
Answer:
???what metal????????????
By the transfer of one or more electrons from one atom to another
for example,
2Na + Cl₂ → 2Na⁺Cl⁻
Na - e⁻ → Na⁺
Cl₂ + 2e⁻ → 2Cl⁻
Answer:
A i. Internal energy ΔU = -4.3 J ii. Internal energy ΔU = -6.0 J B. The second system is lower in energy.
Explanation:
A. We know that the internal energy,ΔU = q + w where q = quantity of heat and w = work done on system.
1. In the above q = -7.9 J (the negative indicating heat loss by the system). w = 3.6 J (It is positive because work is done on the system). So, the internal energy for this system is ΔU₁ = q + w = -7.9J + 3.6J = -4.3 J
ii. From the question q = +1.5 J (the positive indicating heat into the system). w = -7.5 J (It is negative because work is done by the system). So, the internal energy for this system is ΔU₂ = q + w = +1.5J + (-7.5J) = +1.5J - 7.5J = - 6.0J
B. We know that ΔU = U₂ - U₁ where U₁ and U₂ are the initial and final internal energies of the system. Since for the systems above, the initial internal energies U₁ are the same, then we say U₁ = U. Let U₁ and U₂ now represent the final energies of both systems in A i and A ii above. So, we write ΔU₁ = U₁ - U and ΔU₂ = U₂ - U where ΔU₁ and ΔU₂ are the internal energy changes in A i and A ii respectively. Now from ΔU₁ = U₁ - U, U₁ = ΔU₁ + U and U₂ = ΔU₂ + U. Subtracting both equations U₁ - U₂ = ΔU₁ - ΔU₂
= -4.3J -(-6.0 J)= 1.7 J. Since U₁ - U₂ > 0 , U₂ < U₁ , so the second system's internal energy increase less and is lower in energy and is more stable.
