+5
Explanation:
The given radical is PO₄³⁻
To solve this problem, we need to understand what oxidation number entails.
The extent of the oxidation of each atom is expressed by the oxidation number.
Here are some rules for assigning them:
- Elements in an uncombined state or elements that combines with one another, their oxidation number is zero.
- The charge on an ion is its oxidation number
- In an neutral compound, algebraic sum of all the oxidation numbers of all atoms is zero.
- In a radical, the algebraic sum of all the oxidation numbers of the ions is equal to the charge on them.
Oxygen is known to have an oxidation number of -2;
PO₄³⁻
P + 4(-2) = -3
P -8 = -3
P = -3 + 8 = +5
The charge on phosphorus is +5
learn more:
Oxidation number brainly.com/question/2086855
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Answer:
The molecular weight for the compound is 60.1 g/mol
Explanation:
We need to determine the molality of solute to find out the molar mass of it.
We apply the colligative property of freezing point depression:
ΔT = Kf . m . i
If the compound was also found to be nonvolatile and a non-electrolyte,
i = 1.
Freezing T° of pure solvent - Freezing T° of solution = Kf . m
0°C - (-2.05°C) = 1.86°C/m . m
2.05°C / 1.86m/°C = m → 1.10 mol/kg
To determine the moles of solute we used, we can multiply molality by the mass of solvent in kg → 202.1 g . 1kg/1000g = 0.2021 kg
1.10 mol/kg . 0.2021kg = 0.223 moles
Molar mass→ g/mol → 13.39 g / 0.223 mol = 60.1 g/mol
Answer:
These elements show variable oxidation state because their valence electrons in two different sets of orbitals, that is (n-1)d and ns. The energy difference between these orbitals is very less, so both the energy levels can be used for bond formation.
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If the net force is doubled, the acceleration would also be doubled.
This is the answer
Answer:
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