At a room temperature a mixture of sand and water can be separated by
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Answer: The freezing point and boiling point of the solution are and
respectively.
Explanation:
Depression in freezing point:
where,
= freezing point of solution = ?
= freezing point of water =
= freezing point constant of water =
i = vant hoff factor = 1 ( for non electrolytes)
m = molality
= mass of solute (ethylene glycol) = 21.4 g
= mass of solvent (water) =
= molar mass of solute (ethylene glycol) = 62g/mol
Now put all the given values in the above formula, we get:
Therefore,the freezing point of the solution is
Elevation in boiling point :
where,
= boiling point of solution = ?
= boiling point of water =
= boiling point constant of water =
i = vant hoff factor = 1 ( for non electrolytes)
m = molality
= mass of solute (ethylene glycol) = 21.4 g
= mass of solvent (water) =
= molar mass of solute (ethylene glycol) = 62g/mol
Now put all the given values in the above formula, we get:
Thus the boiling point of the solution is
To answer this question, you need to know the concept of half-life, which is how a radioactive material decreases in mass over time.
The half life of U-235 is 703.8 million years. The first part of this problem is to find the scale factor. To do this, divide the time that has past by the half life, like this:
Now, take this scale factor and multiply it by the current mass, like this:
This number is what you add to the current mass to get the original mass. That is because the scale factor showed us that it was just over one half life. Since after one half life, the mass is cut in half, and this is over one half life, when we add to the original it will be a little over double. This equation illustrates the final addition:
I hope this helped you. Fell free to ask any further questions.
The half life of U-235 is 703.8 million years. The first part of this problem is to find the scale factor. To do this, divide the time that has past by the half life, like this:
Now, take this scale factor and multiply it by the current mass, like this:
This number is what you add to the current mass to get the original mass. That is because the scale factor showed us that it was just over one half life. Since after one half life, the mass is cut in half, and this is over one half life, when we add to the original it will be a little over double. This equation illustrates the final addition:
I hope this helped you. Fell free to ask any further questions.