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3 years ago

At a room temperature a mixture of sand and water can be separated by

Chemistry

1 answer:

Norma-Jean [14]3 years ago

5 0

The misture can be separated by filtration.

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

qaws [65]

The question is incomplete, here is the complete question:

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:

$CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)$

In the second step, acetylene, carbon dioxide and water react to form acrylic acid:

$6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

Write the net chemical equation for the production of acrylic acid from calcium carbide, water and carbon dioxide. Be sure your equation is balanced.

Answer: The net chemical equation is written below.

Explanation:

The intermediate balanced chemical reaction are:

(1) $CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)$ ( × 6 )

(2) $6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

To omit acetylene from the net chemical reaction, we multiply Equation (1) by 6.

Equation 1: $6CaC_2(s)+12H_2O(g)\rightarrow 6C_2H_2(g)+6Ca(OH)_2(s)$

Equation 2: $6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

Net chemical equation: $6CaC_2(s)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)+6Ca(OH)_2(s)$

Hence, the net chemical equation is written above.

6 0

2 years ago

Example 13:0.29 grams of a hydrocarbon with vapour density 29 when burnt completely in oxygen produce 448 ml of carbon dioxide a

Juliette [100K]

Answer:

Given, 0.29 g of hydrocarbon produces 448ml of CO2 at STP. then, C2H5 is the emperical formula of hydrocarbon . n = 2 , hence, molecular formula will be C4H10

6 0

2 years ago

How many moles are in 1.5L of 0.40M Na2SO4?

anzhelika [568]

Answer:

0.60 moles of Na₂SO₄

Explanation:

Molarity is an unit of concentration defined as the ratio between moles of solute and liters of solution.

A solution of Na₂SO₄ 0.40M contains 0.40 moles of solute (Na₂SO₄) per liter of solution.

As you have 1.5L of solution, moles of Na₂SO₄:

1.5L × (0.40mol / L) = 0.60 moles of Na₂SO₄

7 0

3 years ago

Can someone please answer this and help me

Alisiya [41]

Answer:

heya

mention your no... dear

5 0

3 years ago

What is simple displacement reaction???give examples.

VARVARA [1.3K]

Answer:

<h2>Hey rose why you deleted my comments</h2>

3 0

2 years ago