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anygoal [31]
3 years ago
14

Suppose that 33.3 J of heat is added to an ideal gas. The gas expands at a constant pressure of 1.45 104 Pa while changing its v

olume from 3.24 10-4 to 8.40 10-4 m3. The gas is not monatomic, so the relation does not apply.(a) Determine the change in the internal energy of the gas.
Chemistry
1 answer:
levacccp [35]3 years ago
5 0

Answer:

ΔU = 25.8 J

Explanation:

The gas absorbs 33.3 J of heat, that is, Q = 33.3 J.

The work (W) of expansion can be calculated using the following expression:

W = -P. ΔV

where,

P is the external pressure

ΔV is the change in volume

W = -1.45 × 10⁴ N . m⁻² × (8.40 × 10⁻⁴ m³ - 3.24 × 10⁻⁴ m³) = -7.48 J

The change in the internal energy (ΔU) is:

ΔU = Q + W

ΔU =  33.3 J + (-7.48 J) = 25.8 J

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Write the balanced chemical equation for the reaction shown here. answer chemistry
Aliun [14]
I found the attached image with the same statement of your question and think it may be very useful for you that I use it to show how to answer this question (furthermore I think it may be the same reaction that you forgot to include).

As you can see, there are one image on the left side and other image on hte right side of the figure.

Those images contains drawings that represent molecules and a legend that permit you to distinguish the kind of atoms in each molecule.

Using that, you can indicate the chemical reaction as the transformation of the molecules on the left side onto the molecules on the right side:

Left side:

3 molecules of CH4 and 3 molecules of N2Cl4

Right side:

3 molecules of CCl4, 3 molecules of N2 and 6 molecules of H2

That is represented as:

3CH4 + 3 N2Cl4 -----> 3 CCl4 + 3N2 + 6H2

And that is the balanced chemical equation for the reaction shown in the figured attached.

I hope this is useful for you..






7 0
3 years ago
PLEASE HELP!!
Musya8 [376]

Rubidium is a alkali metal.

4 0
3 years ago
Read 2 more answers
What is the mass, in grams, of 8 mol of 12c?
Kitty [74]

The mass of 8 mol of ¹²C is 96 g.

Mass = 8 mol × (12 g/1 mol) = 96 g

5 0
2 years ago
Students in a chemistry class added 5 g of Zinc to 50 g of hydrochloric acid. A chemical reaction occurred that produced zinc ch
Vinil7 [7]

Answer:

Mass = 11 g

Explanation:

Given data:

Mass of Zn = 5 g

Mass of HCl = 50 g

Mass of hydrogen gas produced = 6 g

Mass of zinc chloride produced = ?

Solution:

Chemical equation:

Zn + 2HCl    →   ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 5 g / 65.38 g/mol

Number of moles = 0.08 mol

Number of moles of HCl :

Number of moles = mass / molar mass

Number of moles = 50 g / 36.5 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of both reactant with zinc chloride.

              Zn           :           ZnCl₂

               1             :             1

              0.08       :        0.08

            HCl          :         ZnCl₂

              2            :           1

             1.4          :         1/2×1.4 =0.7 mol

The number of moles of zinc chloride produced by Zn are less so it will limiting reactant.

Mass of zinc chloride:

Mass = number of moles × molar mass

Mass = 0.08 mol × 136.3 g/mol

Mass = 11 g

5 0
3 years ago
I need the answer today!
olchik [2.2K]

_____________________________________________

<h2 /><h2 /><h2><u>Solution </u><u>3</u><u> Is The Most Concentrated</u></h2>

<h3>S1:</h3>

M = m/v

= 100ml ÷ 2 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

<h3>S2:</h3>

M = m/v

= 200ml ÷ 5 spoons × 100%

= - 4,000 μg/ppb³

= <u>40% Diluted</u>

<h3>S3:</h3>

M = m/v

= 300ml ÷ 6 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

<h3>S4: </h3>

M = m/v

= 600ml ÷ 8 spoons × 100%

= - 75,000 μg/ppb³

= <u>75% Diluted</u>

_____________________________________________

8 0
2 years ago
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