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anygoal [31]
4 years ago
14

Suppose that 33.3 J of heat is added to an ideal gas. The gas expands at a constant pressure of 1.45 104 Pa while changing its v

olume from 3.24 10-4 to 8.40 10-4 m3. The gas is not monatomic, so the relation does not apply.(a) Determine the change in the internal energy of the gas.
Chemistry
1 answer:
levacccp [35]4 years ago
5 0

Answer:

ΔU = 25.8 J

Explanation:

The gas absorbs 33.3 J of heat, that is, Q = 33.3 J.

The work (W) of expansion can be calculated using the following expression:

W = -P. ΔV

where,

P is the external pressure

ΔV is the change in volume

W = -1.45 × 10⁴ N . m⁻² × (8.40 × 10⁻⁴ m³ - 3.24 × 10⁻⁴ m³) = -7.48 J

The change in the internal energy (ΔU) is:

ΔU = Q + W

ΔU =  33.3 J + (-7.48 J) = 25.8 J

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Octasulfur reacts with pure oxygen to produce sulfur dioxide. Determine the percent
Margaret [11]

Answer:

Octasulfur is just S8. Eight S atoms in

a sort of crown shape. Sulfur Dioxide is a gas, SO2. Does that help?

Explanation:

5 0
3 years ago
Kaillie was talking and was distracted as she stirred sugar into her tea. when she finally noticed, there was a few crystals of
AleksandrR [38]

Answer:

Supersaturated

Explanation:

The tea has absorbed and dissolved as much sugar as it could. If there is sugar left at the bottom, it means the solution is supersaturated because it can't absorb any more.

5 0
3 years ago
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Determine the molar mass of a compound that has a density of 0.1633 g/L at STP.<br> (show work)
hodyreva [135]

Answer:

                     M.Mass  =  3.66 g/mol

Data Given:

                  M.Mass  =  M = ??

                  Density  =  d  =  0.1633 g/L

                  Temperature  =  T  =  273.15 K (Standard)

                  Pressure  =  P  =  1 atm (standard)

Solution:

              Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.

                                             P V = n R T    ---- (1)

Also, we know that;

                       Moles  =  n  =  mass / M.Mass

Or,                                   n  =  m / M

Substituting n in Eq. 1.

                                             P V = m/M R T   --- (2)

Rearranging Eq.2 i.e.

                                             P M = m/V R T   --- (3)

As,

                     Mass / Volume = m/V = Density = d

So, Eq. 3 can be written as,

                                             P M = d R T

Solving for M.Mass i.e.

                                             M = d R T / P

Putting values,

M  =  0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm

M  =  3.66 g/mol

6 0
3 years ago
Give the number of significant figures indicated 6.695
Genrish500 [490]
3 significant figures 

5 0
3 years ago
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Fill in the blanks below using vocabulary terms-reactants, products, limiting reactant, excess reactant.
slamgirl [31]

Answer:

The vocabulary terms are in the correct order.  

Explanation:

The substances that undergo chang are called <em>reactants</em>. They are what create the products. Reactants are on the left side of the equation while the products are on the right side of the equation. The new substances are called <em>products</em>. In other words, what is produced? The products are produced. The reactant that will be used up first is called a <em>limiting reactant</em>. Why? Because it is what limits the reaction. It determines how much products can be made. The reactant that is left over then, is called the <em>excess reactant.</em> That is what is left in excess and does <u>not</u> determine how much product is made.

7 0
3 years ago
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