Answer:
It gets attracted
Explanation:
Materials that attracts magnet gets attracted to the magnet at both the North and South Pole. This can be compared to how neutral objects also gets attracted to the positively and negatively charged rod through the force of polarisation.
By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s
Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:
mass m = 0.170 kg
initial speed u = 6 m/s.
Distance covered s = 61 m
To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V
To do this, let us first calculate the kinetic energy at which the ball move.
K.E = 1/2m
K.E = 1/2 x 0.17 x 
K.E = 3.06 J
The work done on the ball is equal to the kinetic energy. That is,
W = K.E
But work done = Force x distance
F x S = K.E
F x 61 = 3.06
F = 3.06/61
F = 0.05 N
From here, we can calculate the acceleration of the ball from Newton second law
F = ma
0.05 = 0.17a
a = 0.05/0.17
a = 0.3 m/
To calculate the final velocity, let us use third equation of motion.
=
+ 2as
=
+ 2 x 0.3 x 61
= 36 + 36
= 72
V = 
V = 8.485 m/s
Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.
Learn more about dynamics here: brainly.com/question/402617
Answer:
B
Explanation:
because, convection is the transfer of heat between fluid substances/materials
Answer: 0 m
Explanation:
Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:
The trajectory is the <u>path followed by the body</u> (is a scalar quantity).
The displacement is <u>the distance in a straight line between the initial and final position</u> (is a vector quantity).
According to this, in the description Matthew's home is placed at 0 on a number line, then he moves 10 m to the park (this is the distance between the park and Mattew's home), then 15 m to the movie theatre until he finally comes back to his home (position 0). So, in this case we are talking about the <u>path followed by Matthew</u>, hence <u>his trajectory</u>.
However, if we talk about Matthew's displacement, we have to draw a straight line between Matthew's initial position (point 0) to his final position (also point 0).
Now, being this an unidimensional problem, the displacement vector for Matthew is 0 meters.
<span>The momentum of the falcon before collision is 0.6 * 20 = 12000 kgm/s which is actually the momenum of the falcon in the x-component. I had converted 600g to kg. After the collision the x-component of the raven is now mv2cos(thetha) where v2 is the final velocity of the raven and theta is the angle at which the falcon hits the raven. So we have that the falcon's final velocity = 600 * 5 * cos (theta). Likewise, after getting hit the the falcon, the raven's final momentum of is = m2v2cos(theta) = 1.5 * 9 * cos(theta). There's no motion along the y-components. So equating we have, momentum before collision = momentum after collision of the raven + momentum after collision of the falcon.
So we have 12000 = 3000cos(theta) + 13.5cos(theta). Cos(theta)(3000 + 13.5) = 12000. Theta = cos^-1( 12000/3013.5 = 3.98 So theta =</span>