a car collides with a wall. compare the forces exerted by the car on the wall and the wall on the car

Physics

2 answers:

NeTakaya2 years ago

5 0

Mass multiplied by acceleration produces force.

The acceleration is (v - 0)/t in this situation, where t seems to be the time it takes automobile A to come to a stop. According to Newton's third law of motion, the automobile produces this turning force of the wall, however the wall, which really is static and indestructible, forces an equal force back on the car.

According to Newton's third law, each action has an equal and opposite response. On this basis, you may deduce that a car driving into a wall would exert force on the wall. However, since the wall did not move, the automobile receives an equivalent force, causing it to collapse.

<h3>Learn more:</h3>

brainly.com/question/13952508?referrer=searchResults

Helga [31]2 years ago

4 0

Answer:

Newton’s third law states that for every action there is an equal and opposite reaction. Based on this you can say that the car crashing into the wall would put force into the wall. However, because the wall didn’t move it gives an equal force back to the car, probably causing it to crumple.

Explanation:

You might be interested in

As the sun sets on the horizon, its rays are ____________ by the ocean water.

sasho [114]

Ultraviolet Ray and red light sun sets on the horizon

7 0

3 years ago

A nuclear fission power plant has an actual efficiency of 32%. If 0.18 MW of power are produced by the nuclear fission, how much

7nadin3 [17]

Answer:

P₀ = 5.76 x 10⁻² MW

Explanation:

given,

efficiency of the power plant = 32%

Power produced by the nuclear fission = 0.18 MW

the power plant output = ?

using formula of efficiency

$\eta = \dfrac{P_0}{P}$

where P is the power produced in the power plant

P₀ is the power output of the power plant

$\eta = \dfrac{P_0}{P}$

$0.32 = \dfrac{P_0}{0.18}$

P₀ = 0.18 x 0.32

P₀ = 0.0576 MW

P₀ = 5.76 x 10⁻² MW

Power plant output is equal to P₀ = 5.76 x 10⁻² MW

8 0

4 years ago

how much force ks required.to.keep 780 n box moving at constant velocityu across.the floor if friction force betwern the bix and

icang [17]

Answer:

Explanation:you must first make a free body diagram of the block to place all the forces that act on the block there. You will have four forces. The normal force, the weight, the horizontal force in x (which is what they ask to calculate) and the friction force. Then you raise the equations and you clear the values. I attach the solution.