The electron should experience a greater acceleration due to it's significantly smaller mass and should fall through distance "d" in a shorter amount of time.
<u>Explanation:</u>
The electron force can be expressed as F=qE. According to Newton's second law of motion force can be expressed as F=ma. This can be written as a=F/m. Substituting electric force expression for "F" in this equation, we get a=qE/m. This means acceleration is conversely proportional to mass and directly to electric field and charge. This means that proton having significantly larger mass than electron should experience smaller amount of acceleration and would take longer to fall at distance "d".
On the other hand, the electron would experience greater acceleration due to it's significantly smaller mass and would fall faster at distance "d", unlike the situation of proton.
Hey there!:
HCl + MnO2 → MnCl2 + H2O + Cl2
* in HCl the oxidation state of Cl is -1 .
* on the product side the oxidation state is 0 .
* therefore Cl gains electrons .
* in MnO2 the oxidation state of Mn is +4
* in MnCl2 the oxidation state of Mn is +2
Therefore Mn loses electrons
Answer A
Hope That helps!
Answer: A.mol/kg
The SI (international system) unit for molality is mol / kg, or solute moles per kg of peptides. A solution with a molality of 1 mol / kg is often described as "1 molal" or "1 m".
Aluminum? It is a chemical element with the symbol Al and atomic number 13. It is a silvery-white, soft, non-magnetic and ductile metal in the boron group. By mass, aluminium is the most abundant metal in the Earth's crust and the third most abundant element
Answer:
C. The reaction can be broken down and performed in steps
Explanation:
Hess's Law of Constant Heat Summation states that irrespective of the number of steps followed in a reaction, the total enthalpy change for the reaction is the sum of all enthalpy changes corresponding to all the steps in the overall reaction. The implication of this law is that the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states of the system.
To obtain MgO safely without exposing magnesium to flame, the reaction sequence shown in the image attached may be carried out. Since the enthalpy of the overall reaction is independent of the pathway between the initial and final states of the system, the sum of the enthalpy of each step yields the enthalpy of formation of MgO.