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QveST [7]
2 years ago
6

Question in Image answer with explanation please added 20 points

Mathematics
2 answers:
Svet_ta [14]2 years ago
7 0

Answer:

$117,351 JMD

Step-by-step explanation:

It is simple. 1 US dollar is 150.45 JMD, so 780 US dollars should be:

780 * 150.45 = 117,351

Y_Kistochka [10]2 years ago
4 0

Step-by-step explanation:

$1US dollar=$150.45JMD

$780US dollars=?

=$150.45×$780

=$117,351

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Can someone please help me with math.
Damm [24]

Answer:

The answer is 2/10 which simplifies to 1/5

I don't know the second one:(

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3 years ago
A car traveled at a constant speed for 4 hours and covered 144.6 miles. It used 12 gallons of gas to travel this distance. How f
ki77a [65]
The car went 12.05 miles per gallon of gas and went 36.15 miles per hour.

(Just divide the total amount of miles by each value to get both of these answers.)


4 0
3 years ago
The value of n for the equation 5n = 5 11 × 5 3
ExtremeBDS [4]
If you add the two terms on the right, you will get 5^14. 14 is your answer.
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3 years ago
The class treasury contained 30$ in nickels and dimes. If there were 500 coins than how many coins of each type are there?
Alenkasestr [34]
Equation 1.  N+D=500

equation 2   5N+10D=3000
This is for equation 1
N=500-d
Substitute into equations 2 and solve for D
5N+10D=3000
5(500-D)+10D=3000
2500-5D+10D=3000
5D=500
D=100
Lets go back the equation 1
N=500-D
N=500-100
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there are 400 Nickles and 100 Dimes
7 0
3 years ago
Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar
Brrunno [24]

The distance between the two points is d=8.6m

The polar coordinate of A is \left(4.47,296.57\right)

The polar coordinate of B is \left(4.24,135\right)

Explanation:

The two points are A(2,-4) and B(-3,3)

The distance between two points is given by,

d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6

Thus, the distance between the two points is d=8.6m

The polar coordinates of A can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting A(2,-4), we get,

Distance = \sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47

tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43

To make the angle positive, let us add 360,

\theta=360-63.43=296.57

The polar coordinate of A is \left(4.47,296.57\right)

Similarly, The polar coordinate of B can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting B(-3,3), we get,

Distance = \sqrt{(3)^{2}+(3)^{2}}=4.24

tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45

To make the angle positive, let us add 360,

\theta=180-45=135^{\circ}

The polar coordinate of B is \left(4.24,135\right)

5 0
3 years ago
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