AMC 10/12 Student Practice Questions

Mathematics

1 answer:

a_sh-v [17]3 years ago

3 0

Answer:

$\mathrm{C.\:}25$

Step-by-step explanation:

Notice how each congruent square is divided into four equal parts. Since each square has four parts and there are four squares, there are $16$ of these parts in total. Because each of these parts make up $\frac{1}{4}$ of each square, all parts are equal. Therefore, you can count the total number of shaded parts to get your percentage.

The top left and bottom right both have one part shaded each for a total of $2$ parts.

The top right and bottom left have $0.5$ and $1.5$ parts shaded, respectively, for a total of $2$ parts.

Therefore, in total, there are $2+2=4$ parts shaded out of $16$ total parts.

Thus, the percentage of the total area that is shaded is:

$\frac{4}{16}=\frac{1}{4}=\fbox{$25\%$}$ .

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A pound of blueberries costs $3.98 and a pound of clementines costs $2.49. What is the combined cost of 0.6 pound of blueberries

siniylev [52]

The combined cost of 0.6 pound of blueberries and 1.8 pounds of clementines is $ 6.87

Solution:

Given that,

Cost of 1 pound of blueberries = $ 3.98

Cost of 1 pound of clementines = $ 2.49

To find: combined cost of 0.6 pound of blueberries and 1.8 pounds of clementines

Let us first find cost of 0.6 pound of blueberries

cost of 0.6 pound of blueberries = 0.6 x Cost of 1 pound of blueberries

$\rightarrow 0.6 \times 3.98 = 2.388$

Thus, cost of 0.6 pound of blueberries is $ 2.388

Find cost of 1.8 pounds of clementines

cost of 1.8 pound of clementines = 1.8 x cost of 1 pound of clementines

$\rightarrow 1.8 \times 2.49 = 4.482$

Thus, cost of 1.8 pound of clementines is $ 4.482

Find combined cost of 0.6 pound of blueberries and 1.8 pounds of clementines

Combined cost = cost of 0.6 pound of blueberries + cost of 1.8 pound of clementines

Combined cost = 2.388 + 4.482 = 6.87

Thus combined cost of 0.6 pound of blueberries and 1.8 pounds of clementines is $ 6.87

5 0

3 years ago

Arrange the equations in increasing order of the value of their solutions.

Ulleksa [173]

See the explanation

<h2>Explanation:</h2>

The complete question is attached below. In order to solve this problem, we'll use a graphing tool. First of all, we'll say that the LHS is a linear function and the RHS is another linear function, so for each case, we'll have:

$f(x)=g(x)$