The relationship between the equilibrant and the resultant vector is *

Physics

1 answer:

vesna_86 [32]3 years ago

6 0

Answer:

the equilibrant is equal in magnitude but opposite in direction.

Explanation:

In vector algebra, a resultant vector is a single vector that have the same effect as the effect of the net or algebraic sum of two or more vectors.

A resultant vector arises from finding the adding multiple vectors together.

When a group of vectors is replaced by a resultant vector, in order to keep the system of vectors at equilibrium, there is another vector which has the same magnitude as the resultant vector but acting in opposite direction to the resultant vector. This vector is called the equilibrant.

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3 years ago

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A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 4.05 m/s. If the roof is pitched at

AlekseyPX

(a) The time the baseball spends in the air is 0.92 s.

(b) The horizontal distance from the roof edge to the point where the baseball lands on the ground is 3.1 m.

<h3>Time spent in air by the baseball</h3>

h = vt - ¹/₂gt²

-2.1 = (4.05 x sin 34)t - ¹/₂(9.8)(t²)

-2.1 = 2.26t - 4.9t²

4.9t² - 2.26t - 2.1 = 0

t = 0.92 s

<h3>Horizontal distance traveled by the baseball</h3>

R = Vx(t)

R = (4.05 x cos 34)(0.92)

R = 3.1 m

Thus, the time the baseball spends in the air is 0.92 s.

The horizontal distance from the roof edge to the point where the baseball lands on the ground is 3.1 m.

Learn more about horizontal distance here: brainly.com/question/24784992

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2 years ago

A 55.0-kg lead ball is dropped from the Leaning Tower of Pisa. The tower is 55.0 m high. What is the speed of the ball after it

PolarNik [594]

Answer:

The speed of the ball is 9.07 m/s.

Explanation:

Given that,

Mass of the lead ball, m = 55 kg

Height of the tower, h = 55 m

We need to find the speed of the ball it has traveled 4.20 m downward, x = 4.2 meters

The initial speed of the ball will be 0 as it was at rest initially. Let v is the speed of the ball after it has traveled 4.20 m downward. It is a case of equation of motion such that :

$v^2-u^2=2ax$