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Alex17521 [72]
2 years ago
5

A person carries a box of 100 kg. What is the weight of the box? (g= 9.8 m/s2)​

Physics
1 answer:
aliina [53]2 years ago
8 0

Answer:

980 newton

Explanation:

100×9.8 = 980

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3 years ago
Kyle and Jenny both have pet rabbits. They wanted to see who had the fastest rabbit, so they each recorded data at their homes a
jekas [21]

Answer:

v_kyle = 0.5 m/s

v_jennies = 0.333 m/s

Kyle's Rabbit was the fastest

Explanation:

For the velocity of Kyle's Rabbit:

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t = time taken = (1 min)(60s/1 min) + 20 s = 80 s

v_{kyle} = \frac{d}{t} = \frac{40\ m}{80\ s}

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For the velocity of Jennies Rabbit:

d = distance covered = 30 m

t = time taken = (1 min)(60s/1 min) + 30 s = 90 s

v_{jennies} = \frac{d}{t} = \frac{30\ m}{90\ s}

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It is clear from the results that:

<u>Kyle's Rabbit was the fastest</u>

7 0
3 years ago
How many grams of CO-60 result in 1 Millicuire of activity? How many years until the activity decays to 1 microcuire tl/2 =5.3 Y
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Answer:

m =8.81*10^{-6}grams

time t = 52.8 year

Explanation:

GIVEN DATA:

the half life of the CO-60 is, T_1/2 = 5.27 years = 1.663 e+8 s

activity dN/dt = 1 mCi = 3.7 X 10^7 decay/s

activity ,  dN/dt = N* \lambda

              \frac{dN}{dt} = N* \frac{ln2}{T_1/2}

                   N = \frac{(dN/dt )(T1/2)}{ln2}

                      = ( 3.7 X 10^7 )(1.663*10^8 ) / ln2

                      = 8.877*10^{16}

Number of moles:

     n = N/NA = 8.877*10^{16} / 6.022X10^23 = 1.474*10^{-7} mol

mass of the CO-60 is,

   m = n*M = [1.474*10^{-7} mol]*[59.93 grams /mol] = 8.81*10^{-6}grams

-----------------------------------------------------------------------------------------

    time t = -[T1/2 / ln2]*ln[N/N0]

             = - [5.3 years / ln2]*ln[1x10-6/1x10-3]

             = 52.8 year

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3 years ago
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