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DedPeter [7]
3 years ago
7

How many liters are in 4.5 moles of CO2 gas at STP? Pls help :)

Chemistry
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

Explanation:

NCO 2= 4,5

VCO2=  4,5* 22,4=100,8

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3 years ago
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An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

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3 years ago
What molecules can form hydrogen bonds?
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How many moles are in 2.4g of carbon dioxide (CO2)?
miv72 [106K]

Answer:

\boxed {\boxed {\sf 0.055 \ mol \ CO_2}}

Explanation:

To convert form grams to moles, the molar mass must be used. This is the mass (in grams) in 1 mole of a substance.

We can use the values on the Periodic Table. First, find the molar masses of the individual elements: carbon and oxygen.

  • C: 12.011 g/mol
  • O: 15.999 g/mol

Check for subscripts. The subscript of 2 after O means there are 2 oxygen atoms, so we have to multiply oxygen's molar mass by 2 before adding.

  • O₂: 2* (15.999 g/mol)=31.998 g/mol
  • CO₂: 12.011 g/mol + 31.998 g/mol =40.009 g/mol

Use the molar mass as a ratio.

\frac {44.009 \ g\ CO_2}{ 1 \ mol \ CO_2}

Multiply by the given number of grams.

2.4 \ g \ CO_2 *\frac {44.009 \ g\ CO_2}{ 1 \ mol \ CO_2}

Flip the fraction so the grams of carbon dioxide cancel.

2.4 \ g \ CO_2 *\frac { 1 \ mol \ CO_2}{44.009 \ g\ CO_2}

2.4  *\frac { 1 \ mol \ CO_2}{44.009}

\frac { 2.4 \ mol \ CO_2}{44.009}= 0.0545342998 \ mol \ CO_2

The original measurement of grams has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

The ten thousandth place has a 5, so we round the 4 to a 5.

0.055 \ mol \ CO_2

2.4 grams of carbon dioxide is about 0.055 moles.

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3 years ago
Who discovered the electron and what instrument did he use?
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