Answer:
the acceleration of the race car is 2 m/s²
Explanation:
Given;
initial velocity of the race car, u = 44 m/s
final velocity of the race car, v = 66 m/s
time of motion of the race car, t = 11 s
The acceleration of the race car is calculated as;

Therefore, the acceleration of the race car is 2 m/s²
This is in the thermosphere which is at an altitude of 85-520km
You would do distance divided by speed. So 150÷3, which would equal 5km per hour.
The Kinetic energy would be 1/2IL².
<h3>What is
Rotational Kinetic energy ?</h3>
- Rotational energy also known as angular kinetic energy is defined as: The kinetic energy due to the rotation of an object and is part of its total kinetic energy. Rotational kinetic energy is directly proportional to the rotational inertia and the square of the magnitude of the angular velocity.
As we know linear Kinetic energy = 1/2mv²
where m= mass and v= velocity.
Similarly rotational kinetic energy is given by = 1/2IL²
where I- moment of inertia and L=angular momentum.
To know more about the Kinetic energy , visit:
brainly.com/question/29807121
#SPJ4
-40 c = -40 f but k would be 233.15