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2 years ago

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Mathematics

2 answers:

victus00 [196]2 years ago

7 0

I think it is B {(0,2), (1,0))

Zanzabum2 years ago

6 0

Answer:

Step-by-step explanation:

I had this question a few months back and I think this was the answer not too sure though

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mrs. Cleaver mix is 1.24 liters of red paint with three times as much blue paint to make purple paint. She put the paint equally

Jet001 [13]

When it says in each cup, I'mg guessing it means containers... so I'll go with that! If you need 3 times as much blue for red to make purple then:

1.24 liters × 3 = 3.72 liters of blue paint per container.

If I am wrong, please go from there with the blue per container. I hope this helped!

5 0

3 years ago

What is the area of a circle with a diameter of 23 centimeters? Use 3.14 for pi. Enter your answer, as a decimal, in the box.

Travka [436]

The equation for the area of a circle is A = PI x r^2

R = radius, which is half the diameter = 23/2 = 11.5

Area = 3.14 x 11.5^2

Area = 3.14 x 132.25

Area = 415.265 square cm.

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2 years ago

A survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the resul

pav-90 [236]

Answer:

95% confidence interval for the proportion of the adults who were opposed to the death penalty is (0.668, 0.704).

Step-by-step explanation:

We are given that a survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the results below, where X refers to the number of the respondents who were in favor.

X = 1,790

N = 2,610

$\hat p$ = Sample proportion = X/N = 0.6858

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.6858

n = sample of respondents = 2,610

p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at

2.5% level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]