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zloy xaker [14]
3 years ago
7

A chemist performs the same tests on two white solids, A and B. The results are shown in the table below.

Chemistry
2 answers:
Ber [7]3 years ago
6 0
I’m pretty sure it’s A well I think sorry if its not but I hope it helps
Roman55 [17]3 years ago
4 0

Answer:

i'm not sure but mabey A?

Explanation:

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There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
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\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

  • m(\text{Hg}) = m(\text{residure})
  • m(\text{O}) = m(\text{loss})

First compound:

  • m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g
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n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
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Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012  \; g

n = m/M; 0.4172 \; g of the first compound would contain

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  • n(\text{Hg atoms}) = 0.4012 \; g  / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol

n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

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3 years ago
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Answer:

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Explanation:

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What is the correct order of coefficients to balance this equation?
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Answer:

2Al + 3CuSO4 → Al2(SO4)3 + 3Cu

Explanation:

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