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2 years ago

A chemist performs the same tests on two white solids, A and B. The results are shown in the table below.

Chemistry

2 answers:

Ber [7]2 years ago

6 0

I’m pretty sure it’s A well I think sorry if its not but I hope it helps

Roman55 [17]2 years ago

4 0

Answer:

i'm not sure but mabey A?

Explanation:

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2 What do you notice about the location of the elements in each family?

sleet_krkn [62]

Explanation:

They are indeed placed from the far left hand side of the periodic table in almost the same column. If you step around the table between left to right, the movement of electrons rises by one. When you progress down the line, the number of power increases by the one.

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2 years ago

When 2.5 g of blue copper(ii) sulfate crystals were heated, 1.6 g of a white solid were left in tube A

Zinaida [17]

Answer:

b po answerpa brainlest

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2 years ago

If 5.0 liters H2 (g) at STP is heated to a temperature of 985, pressure remaining constant, the new volume of the gas will be?

vlada-n [284]

Answer:

$V_2=18 \ L \ H_2$

General Formulas and Concepts:

Chemistry - Gas Laws

STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Charles' Law: $\frac{V_1}{T_1} =\frac{V_2}{T_2}$

Explanation:

Step 1: Define

Initial Volume: 5.0 L H₂ gas

Initial Temp: 273 K

Final Temp: 985 K

Final Volume: ?

Step 2: Solve for new volume

Substitute: $\frac{5 \ L \ H_2}{273 \ K} =\frac{x \ L \ H_2}{985 \ K}$
Cross-multiply: $(5 \ L \ H_2)(985 \ K) = (x \ L \ H_2)(273 \ K)$
Multiply: $4925 \ L \ H_2 \cdot K = 273x \ L \ H_2 \cdot K$
Isolate x: $18.0403 \ L \ H_2 = x$
Rewrite: $x=18.0403 \ L \ H_2$

Step 3: Check

We are given 2 sig figs as the smallest. Follow sig fig rules and round.

$18.0403 \ L \ H_2 \approx 18 \ L \ H_2$

5 0

2 years ago

How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.

Gekata [30.6K]

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

No.of moles=mass in gram/molar mass

As for Fe mole =156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed= 2.797x3/2=4.1955

Mass of CO needed= 4.195mol x 28.01g/mol= 117.515g

8 0

3 years ago

A fish is removed from a contaminated lake. You determine that a particular toxin (X) is present in its cells at concentration X

netineya [11]

The level of toxins in the fish's cell is equivalent to the level of toxins in the water. Therefore, in order to reduce the toxins further, we should replace the now contaminated water with clean water. After the level of toxins in the fish's cell stops reducing, we replace the water with clean water once again.

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2 years ago