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2 years ago

A chemist performs the same tests on two white solids, A and B. The results are shown in the table below.

Chemistry

2 answers:

Ber [7]2 years ago

6 0

I’m pretty sure it’s A well I think sorry if its not but I hope it helps

Roman55 [17]2 years ago

4 0

Answer:

i'm not sure but mabey A?

Explanation:

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What is the formula for germicide that is sufficient to kill blood-borne pathogens?

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It is 1 ounce. Bloodborne Pathogens can be transmitted when blood or body liquid from a tainted individual enters someone else's body by means of needle-sticks, human chomps, cuts, scraped areas, or through mucous films. Likewise, semen, vaginal discharges and salivation in dental methods are considered conceivably tainted body liquids.

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2 years ago

Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.

Misha Larkins [42]

Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

$moles HCl = moles KOH \\ \\ cHCl*vHCl=cKOH*vKOH \\ \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}= 541,54mL$

So, the required volume of HCl is 541,54 mL

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2 years ago

The _______ geometry of a water molecule is tetrahedral even though the molecular geometry is bent

IRINA_888 [86]

The electron geometry of a water molecule is tetrahedral even though the molecular geometry is bent.

As water molecule hybridisation is sp³ that provides it a electron geometry tetrahedral but due to presence of 2 lone pairs and 2 bond pairs its molecular geometry is bent.

The hybridisation sp³ makes electron geometry of a water molecule tetrahedral but the presence of 2 lone pairs makes its molecular geometry bent

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2 years ago

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Na = ? Periodic Table

8_murik_8 [283]

Answer:

Na on the periodic table is sodium.

Hope this was useful to you

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2 years ago

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The tosylate of (2R,3S)-3-phenylbutan-2-ol undergoes an E2 elimination on treatment with sodium ethoxide. Draw the structure of

andrezito [222]

Answer:

(R)-but-3-en-2-ylbenzene

Explanation:

In this reaction, we have a very strong base (sodium ethoxide). This base, will remove a hydrogen producing a double bond. We know that the reaction occurs through an E2 mechanism, therefore, the hydrogen that is removed must have an angle of 180º with respect to the leaving group (the "OH"). This is known as the anti-periplanar configuration.

The hydrogen that has this configuration is the one that placed with the dashed bond (red hydrogen). In such a way, that the base will remove this hydrogen, the "OH" will leave the molecule and a double bond will be formed between the methyl and the carbon that was previously attached to the "OH", producing the molecule (R) -but-3- en-2-ylbenzene.

See figure 1

I hope it helps!

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2 years ago