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Ivahew [28]
2 years ago
7

What is the molarity of an HCl solution if 43.6 mL of a 0.125 M NaOH solution are needed to titrate a 25.0 mL sample of the acid

according to the equation below (show your calculations)? NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq)
Chemistry
1 answer:
Sveta_85 [38]2 years ago
3 0

Answer: The molarity of an HCl solution is 0.218 M if 43.6 mL of a 0.125 M NaOH solution are needed to titrate a 25.0 mL sample of the acid.

Explanation:

Given: V_{1} = 43.6 mL,      M_{1} = 0.125 M

V_{2} = 25.0 mL,        M_{2} = ?

Formula used to calculate the concentration of acid is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula.

M_{1}V_{1} = M_{2}V_{2}\\0.125 M \times 43.6 mL = M_{2} \times 25.0 mL\\M_{2} = 0.218 M

Thus, we can conclude that the molarity of an HCl solution is 0.218 M if 43.6 mL of a 0.125 M NaOH solution are needed to titrate a 25.0 mL sample of the acid.

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