Given the reaction:

A 8.249 gram sample of copper is heated in the presence of excess fluorine. A metal fluoride is formed with a mass of 13.18 g. D

levacccp [35]

Answer:

$CuF_2$ the empirical formula of the metal fluoride.

Explanation:

Mass of copper heated = 8.249 g

Mass of copper fluoride formed = 13.18 g

Mass of fluorine gas in copper fluoride = x

$13.18 g = 8.249 g + x\\x= 13.18 - 8.249 g = 4.931 g$

Moles of copper :

$= \frac{8.249 g}{63.546 g/mol}=0.1298 mol$

Moles of fluorine:

$= \frac{4.931 g}{18.998 g/mol}=0.2596 mol$

For the empirical formula divide the smallest mole of an element with all the moles of elements present in the compound.

$Copper= \frac{0.1298 mol}{0.1298 mol}=1\\Fluorine = \frac{0.2596 mol}{0.1298 mol}=2$

The empirical formula of the copper fluoride = $CuF_2$

$CuF_2$ the empirical formula of the metal fluoride.

6 0

3 years ago

Please help. QUICK LIMITED TIME

Serggg [28]

The energy of a nuclear reactor gets converted to electricity by using steam. As steam converts mechanical energy to electricity.

Answer: Option C

<u>Explanation: </u>

Nuclear reaction works on the principle of nuclear fission. The main functioning of nuclear reactor is the generation of neutrons by fission of Uranium oxide.

The rate of generation of neutrons need to be controlled in the reaction to have a controlled chain reaction which is suitable for generating electricity.

So, the controlling of rate of nuclear generation is done by moderators. The moderators are generally water or graphite in any nuclear reactor. So during these process, steam is produced in the reactor core which then flows through a turbine engine.

The steam rotates the turbines in the generator and thus the mechanical energy of the turbine during rotation is converted as the electrical energy in the generator.

5 0

3 years ago

What is the mole ratio of PCl3 to PCl5?

Ray Of Light [21]

It 1:1 I had an online review and thats the answer it told me it was.
-Hope this helped you

8 0

3 years ago

Read 2 more answers

If it takes 87.0 min for the concentration of a reactant to drop to 20.0% of its initial value in a first-order reaction, what i

charle [14.2K]

Answer:

0.0185 min⁻¹

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

20.0 % of the initial values is left which means that 0.20 of $[A_0]$ is left. So,

$\frac {[A_t]}{[A_0]}$ = 0.20

t = 87.0 min

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.20=e^{-k\times 87.0}$

4 0

4 years ago

Go to the To Scale tab at the bottom of the simulation, and select Path from the central menu on the right. Set up a Planet-Moon

snow_lady [41]

Answer:

Go to the To Scale tab at the bottom of the simulation, and select Path from the central menu on the right. Set up a Planet-Moon simulation. Use the sliders to make both the planet and the moon as massive as possible, and then ... What do you notice about the moon's motion when it is closest to the planet?

Explanation:

3 0

3 years ago