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Alinara [238K]
3 years ago
15

sodium ions are moving with their concentration gradient with the use of a protein channel across a plasma membrane. Determine t

he type of membrane transport used to transport these sodium ions
Chemistry
2 answers:
jeka57 [31]3 years ago
6 0

Answer:

Explanation:

When there is difference between the concentration of the content of a cell and the solution surrounding the cell, there will be an Electrochemical gradient or Concentration gradient. Therefore, some solute will tend to move from the region of high concentration to the region of lower concentration through the cell membrane.

Such a movement is called Primary Active Transport

Ilya [14]3 years ago
6 0

Answer: the membrane transport used is "facilitated diffusion"

Explanation:

Facilitated diffusion transport (passive transport) is a spontaneous transport of molecules or ions across a biological membrane via membrane Proteins that act as mediators. These membrane Proteins (transporters or permeases) speed up the movement of solutes across the membrane by facilitating diffusion.

Sodium ion, glucose ions and some other ions need to be transported across d plasma membrane which is made of lipid bilayer that is impermeable. For this transport to occur, a mechanism of bypassing or creating an alternative path across the plasma membrane is needed. This mechanism is performed by permeases(membrane proteins).

The membrane proteins act as transport facilitator by lowering the activation energy for effective transport of polar compound and ions.

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Intercourse between two beings, usually male and female to procreate.
6 0
3 years ago
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The amount of radioactive carbon-14 in a sample is measured using a Geiger counter, which records each disintegration of an atom
sergij07 [2.7K]

Answer:

4121 years

Explanation:

From;

0.693/t1/2 = 2.303/t log No/N

t1/2= half life of the carbon-14

No= count rate of the living tissue

N= count rate of the sample

t = age of the sample

0.693/5730 =2.303/t log (13.5/8.2)

1.21 * 10^-4 = 2.303/t * 0.2165

1.21 * 10^-4 = 0.4986/t

t = 0.4986/1.21 * 10^-4

t = 4121 years

7 0
3 years ago
Group I elements are metals with ................. density
kherson [118]

group 1 elements are metals with<u> low</u> density

8 0
3 years ago
When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed? 2Al + 6HCl → 2AlCl
4vir4ik [10]

Well, we need to find the ratio of Al to the other reactant.


Al:HCl = 1:3


--> this means that for every 1 Al used, you have to use 3 HCl.



6*3 = 18 moles of HCl needed to fully react with 6 moles of Al. Since 13<18, HCL is the limiting reactant.



The ratio of HCl:AlCl = 3:1



13/3 = 4.3333...



The final answer is HCl is the limiting reactant with 4.3 moles of AlCl3 able to be produced.



Hope this helps!!! :)


6 0
3 years ago
How many grams of h2 are needed to produce 14.51 g of nh3?
gavmur [86]

Answer:

               2.57 g of H₂

Solution:

The Balance Chemical Equation is as follow,

                                          N₂  +  3 H₂    →    2 NH₃

According to Balance equation,

         34.06 g (2 moles) NH₃ is produced by  =  6.04 g (3 moles) of H₂

So,

               14.51 g of NH₃ will be produced by  =  X g of H₂

Solving for X,

                      X  =  (14.51 g × 6.04 g) ÷ 34.06 g

                     X =  2.57 g of H₂

7 0
3 years ago
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