Answer:
Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789
Answer:
The frequencies are 
Explanation:
From the question we are told that
The length of the ear canal is 
The speed of sound is assumed to be 
Now taking look at a typical ear canal we see that we assume it is a closed pipe
Now the fundamental harmonics for the pipe(ear canal) is mathematically represented as

substituting values


Also the the second harmonic for the pipe (ear canal) is mathematically represented as
substituting values
Given that sound would be loudest in the pipe at the frequency, it implies that the child will have an increased audible sensitivity at this frequencies
Newton has 3 Laws specifically The Three Laws of Motion
<span>Reducing the distance between them. In theory, also increasing the mass; but you can't really change the mass of an object. However, you can compare the forces if you replace an object by a different object, which has a different mass.
</span>
i hope this will work..
Answer:
a)<em> 2000 W/m² </em><em>; </em>b) 636.94 W/m<em>².sr ; </em><em>c) </em>0.5
Explanation:
a)
The formula for calculation of total emissive power is:
Total emissive power = E =
E'<em>λdλ</em>
<em> </em>=
(0)d<em>λ + </em>
(100)d<em>λ + </em>
(200)d<em>λ + </em>
(100)d<em>λ </em>
(0)d<em>λ</em>
<em>where a = 5; b = 10; c = 15; d = 20; e = 25</em>
<em> = 0 +100(10-5) + 200(15-10) +100(20-15) + 0</em>
<em> = 2000 W/m²</em>
b)
The formula for total intensity of radiation is:
I
= E/π = 200/3.14 = 636.94 W/m<em>².sr </em>
<em>c)</em>
Fo submissive power leaving the surface in range π/4 ≤θ≤π/2
[E(π/4 ≤θ≤π/2)]/E = 

Icosθsinθ dθdΦdλ
where f = infinity, g=2π, h=π/4, i=π/2
By simplifying, we get
= (-1/2)[cos(2π/2)-cos(2π/2)]
= -0.5(-1-0)
=0.5