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sesenic [268]
3 years ago
9

A 1.5m wire carries a 6 A current when a potential difference of 70 V is applied. What is the resistance of the wire?

Physics
1 answer:
nalin [4]3 years ago
6 0

From Ohm's law:  R = V / I

Resistance = (voltage) / (current)

Resistance = (70 volts) / (6 Amperes)

<em>Resistance = 11.67 ohms</em>

(We don't need to know the length, thickness, color, or cost of the wire.)

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Galina-37 [17]

Ozone in troposphere is also know as Bad Ozone, Evil Ozone and Ground Level Ozone.

5 0
3 years ago
A- 1000 m/s2<br> Xi-0m<br> Xf-0.75m<br> Vf-?
sleet_krkn [62]

Answer:

The final velocity of the object is,  v_{f} = 27 m/s    

Explanation:

Given,

The acceleration of the object, a = 1000 m/s²

The initial displacement of the object, x_{i} = 0 m

The final displacement of the object,  x_{f} = 0.75 m

The initial velocity of the object will be, v_{i} = o m/s

The final velocity of the object, v_{f} = ?

The average velocity of the object,

                                    v = ( x_{f} - x_{i} )/ t

                                      = 0.75 / t

The acceleration is given by the relation

                                     a = v / t

                                   1000 m/s² = 0.75 / t²

                                            t² = 7.5 x 10⁻⁴

                                            t = 0.027 s

Using the I equation of motion,

                                  v_{f} = u + at

Substituting the values

                                   v_{f} = 0 + 1000 x 0.027

                                                           = 27 m/s

Hence, the final velocity of the object is,  v_{f} = 27 m/s          

8 0
3 years ago
If you wanted to find the area of the hot filament in a light bulb, you would have to know the temperature (determinable from th
Sladkaya [172]

Answer:

To find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and <u>Emissivity of the Filament</u>.

Explanation:

The emissive power of a light bulb can be given by the following formula:

E = σεAT⁴

where,

E = Power Input or Emissive Power

σ = Stefan-Boltzmann constant

ε = Emissivity

A = Area

T = Absolute Temperature

Therefore,

A = E/σεT⁴

So, to find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and <u>Emissivity of the Filament</u>.

3 0
3 years ago
There are two types of magnets some of them are _______ and some are _________
kogti [31]

Answer:

There are many types of magnets, which are generally divided into two categories: permanent magnet and a soft magnet.

Explanation:

8 0
2 years ago
Read 2 more answers
Qualitative studies draw conclusions.<br> True<br> False
Marina86 [1]

Answer:

Hey there!

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Let me know if this helps :)

3 0
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