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Serjik [45]
3 years ago
12

Explain the sharing of electrons between a water molecule that forms four hydrogen bonds with the other four water molecules

Chemistry
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

The sharing of electrons between a water molecule that forms four hydrogen bonds with the other four water molecules:

Explanation:

The hydrogen bond is a weak electrostatic force of attraction that exists between a covalently bonded H-atom and a highly electronegative atom like N,O or F.

In the case of the water molecule,

the highly electronegative atom is Oxygen and the intermolecular hydrogen bond in water is as shown below:

Thus H-bond is a weak electrostatic attraction formed between H-atom and O-atom in water.

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Liquid A and liquid B form a solution that behaves ideally according to Raoult's law. The vapor pressures of the pure substances
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Answer:

Vapor pressure of solution → 151.1 Torr

Option 2.

Explanation:

Raoult's Law is relationed to colligative property about vapor pressure. A determined solute, can make, the vapor pressure of solution decreases.

ΔP = P° . Xm

where Xm is the mole fraction of solute, P° (vapor pressure of pure solvent)

and ΔP = Vapor pressure of pure solvent - Vapor pressure of solution.

In order to determine the vapor pressure of solution, we need to determine, the vapor pressure of B and A in the solution

B's pressure = P° B . Xm

When we add A to B, A works as the solute and B, as the solvent.

Vapor pressure of pure B is 135 torr. (P° B)

In order to determine, the Xm, we use the moles of A and B

Xm = 5.3 mol of B / (1.28 + 5.3) → 0.806

B's pressure = 135 Torr . 0.806 → 108.81 Torr

If mole fraction of B is 0.806, mole fraction for A (solute) will be (1 - 0.806)

A's pressure = 218 Torr . 0.194 → 42.3 Torr

Vapor pressure of solution is sum of vapor pressures of solute + solvent.

Vapor pressure of solution = 42.3 Torr + 108.81 Torr → 151.1 Torr

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