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2 years ago

What effect does salt have on a marshmallow?

Chemistry

1 answer:

Naily [24]2 years ago

3 0

Answer:

The original marshmallow was named for the inclusion of marshmallow root in the recipe. The roots and leaves of the marshmallow plant contain mucilage, a slimy-textured demulcent best known for its use as a homeopathic cough suppressant. Marshmallow root is considered to be soothing and mildly antimicrobial. It has long been used as an herbal treatment for minor digestive issues and skin irritations, although its use in the creation of its namesake confection has long since fallen by the wayside.

Explanation:

So basically salt makes it strecthy! Please mark brainliest!!

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

Scorpion4ik [409]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.

Explanation:

Step 1 : Calcium carbide and water react to form acetylene and calcium hydroxide

$CaC_2(s)+2H_2O(g)\rightarrow$

$C_2H_2(g)+Ca(OH)_2(s),\Delta H_1=-414 kJ$ ..[1]

Step 2 : Acetylene, carbon dioxide and water react to form acrylic acid

$6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCOOH(g),\Delta H_2=132 kJ$ ..[2]

Using Hess's law:

[1] × 6 + [2]

$6CaC_2(s)+16H_2O(g)+3CO_2\rightarrow 5CH_2CHCOOH(g)+6Ca(OH)_2(s),\Delta H_3=?$

$\Delta H_3=6\times \Delta H_1+\Delta H_2$

$\Delta H_3=6\times (-414 kJ)+132 kJ=-2352 kJ$

The energy released on formation of 5 moles of acrylic acid = -2352 kJ

The energy released on formation of 1 moles of acrylic acid :

$=\frac{-2352 kJ}{5 mol}=-470.4 kJ/mol$

Hence, the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.

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2 years ago

A solution of 6.2 M H2SO4 is diluted from 2.0 L to 3.0 L. What is the molarity of the resulting solution?

makkiz [27]

Answer:

H⁣⁣⁣⁣ere's l⁣⁣⁣ink t⁣⁣⁣o t⁣⁣⁣he a⁣⁣⁣nswer:

bittuly/3a8Nt8

Explanation:

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2 years ago

What happens when you shoot a neutron at a uranium-238 atom?

serious [3.7K]

Answer: Scientist shoot a whole bunch of neutrons at uranium-235 atoms. When one neutron hits the nucleus the uranium becomes U-236. When it becomes 236, the uranium atoms wants to spilt apart. After it splits it gives off three neutrons and a lot of energy.

Explanation:

7 0

2 years ago

What is the density of chlorine gas (MM = 71.0glmol) at 1.50 atm and 25.0C

IrinaVladis [17]

Answer: D=4.35g/L

Explanation:

The formula for density is $D=\frac{M}{V}$ . M is mass in grams and V is volume in liters.

Since we are give pressure and temperature, we can use the ideal gas law to find moles/volume. FInding moles/volume would give us the base for density. All we would have to do is convert moles to grams.

Ideal Gas Law: PV=nRT

$\frac{n}{V} =\frac{P}{RT}$