The solution for this problem is:
Remember that this doesn’t depend on the mass of the child.
E = T + U = constant
E (maximum height) = T + U =U = mgh = mg[r - r· cos (Θ)]
E (bottom height) = T + U = T = ½mv² = mg[r - r · cos (Θ)]
v² = 2g[r – r · cos (Θ)]
v = √ (2g[r-r·cos(Θ)])
= √(2(9.8)[3 – 3 · cos (45°)])
= 4.15 m/s or 15 kph
Search Results<span>Use BFS to determine the length of the shortest v-w-path. Then use DFS to find thenumber of the v-w-shortest paths such that two nodes are connected and the length of path equals to the output of BFS. But the running time of this plan is O(m+n)+O(m+n). Also I've tried to modify the Dijkstra algorithm.</span>
Answer:
7327 kg or 7.3 tons
Explanation:
We have Newton formula for attraction force between 2 objects with mass and a distance between them:
where 
is the gravitational constant on Earth. 
is the masses of the 2 objects. and R = 2.6m is the distance between them.
is the attraction force.
or 7.3 tons
Answer:
Fundamental frequency is 70.12 m
Explanation:
For an open organ pipe, the fundamental frequency is given by :
n = 1 for fundamental frequency
v is speed of sound in air, v = 345 m/s
l is length of open organ pipe, l = 2.46 m
Substituting values in above formula. So,
So, the fundamental frequency of this pipe is 70.12 m.
C is the correct answer but the best possible answer is that work is done when a force is imposed on an object and the object moves in the same direction as the force
Hope this helps!
