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balandron [24]
2 years ago
7

HEEEYYYYY HELLO CAN YOU HELP ME WITH THIS ? PLEASE? ​

Physics
1 answer:
Lubov Fominskaja [6]2 years ago
4 0

Answer:

Here are the names and symbols

H is Hydrogen

Au is Gold

Potassium is K

Mg is Magnesium

Zinc is Zn

Iron is Fe

Cl is Chlorine

Na is Natrium/Sodium

Copper is Cu

Ag is Silver

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Find the length of an arc with a radius of 6.0m swept across 2.5 radians.
soldier1979 [14.2K]

Hello!

In terms of an arc length, radians is the measurement of an arc length in terms of the original radius. This arc length is 2.5 radians, so we multiply it by our original radius.

2.5(6)=15

Therefore, the arc length is 15 meters.

I hope this helps!


7 0
3 years ago
A dog runs with an initial velocity of 7.5 m/s on a waxed floor. It slides to a stop in 15 seconds. What is the acceleration?
Leni [432]

Answer:

-0.5 m/s^2

Explanation:

Acceleration = change in velocity / total time

7.5 / 15 = 0.5

3 0
2 years ago
Compute the work performed when 32 pounds is lifted 10 feet.
Murljashka [212]
W = force * displacement
W = 32 pounds * 10 feet
Now you need to convert it to newton and meters
W = 142 N * 3.048 m = 434 J
(I approximated the conversions- I hope it helps)
7 0
3 years ago
What did scientists predict the big bang should have left ??
ELEN [110]
<span>radiation, hydrogen, and helium </span>
4 0
3 years ago
Read 2 more answers
A 6 kg box with initial speed 5 m/s slides across the floor and comes to a stop after 1.9 s. What is the coefficient of kinetic
Ilia_Sergeevich [38]

Answer:

\mu_k=0.27

Explanation:

According to the free body diagram, in this case, we have:

\sum F_x:-F_k=ma\\\sum F_y:N=mg

Recall that the force of friction is given by:

F_k=\mu_k N

Replacing and solving for the coefficient of kinetic friction:

-\mu_kN=ma\\-\mu_k(mg)=ma\\\mu_k=-\frac{a}{g}

We have an uniformly accelerated motion. Thus, the acceleration is defined as:

a=\frac{v_f-v_0}{t}\\a=\frac{0-5\frac{m}{s}}{1.9s}\\a=-2.63\frac{m}{s^2}

Finally, we calculate \mu_k:

\mu_k=-\frac{-2.63\frac{m}{s^2}}{9.8\frac{m}{s^2}}\\\mu_k=0.27

4 0
3 years ago
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