Answer: 1×10^11
Explanation:
<u>concept to know:</u> scientific notation must be written in the form of a × 10^b
where 0<a<10.
100 billion= 100,000,000,000
there are 11 zeros after 1
1 × 10^11
Hope this helps!! :)
Answer:
Whether barium chloride solution was pure
Explanation:
We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:


Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

This means in 10.0 g, we have a total of:
of barium cations.
The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:
- if this number is equal to 6.595 g, we have a pure sample of barium chloride;
- if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.
This is a chemical reaction because a precipitate (solid) was formed from 2 liquids, and there was a color change as well
Answer:
The most stable conformation of the following compound has
A. An axial methyl group and an axial ethyl group.
B. An axial methyl group and an equatorial ethyl group.
C. An axial tert-butyl group.
D. An equatorial methyl group and an equatorial ethyl group.
E. An equatorial methyl group and an axial ethyl group.
Explanation:
The most stable conformation in the cyclohexane ring is the one in which both the substituents are in the equatorial position.
Among the given options,
option D An equatorial methyl group and an equatorial ethyl group.
When the substituents in the cyclohexane ring are in equatorial positions then, the steric repulsions will be reduced.
Answer is option D.
Hello!
When aqueous solutions of Li₂SO₄ and NaI are mixed the following reaction occurs:
Li₂SO₄(aq) + 2NaI(aq) → 2LiI(aq) + Na₂SO₄(aq)
The compounds produced from this reaction are all soluble, so no precipitate is formed. We know that those compounds (LiI and Na₂SO₄) are soluble because of the solubility rules which states that salts from Group I elements (Li⁺, Na⁺) are soluble.
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