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Irina-Kira [14]
3 years ago
7

Which of these elements has two valence electrons? A. hydrogen (H) B. barium (Ba) C. nitrogen (N) D. krypton (Kr) E. bromine (Br

)

Chemistry
2 answers:
oksian1 [2.3K]3 years ago
8 0

Barium has two valence electrons

9966 [12]3 years ago
3 0
So whenever you need to find valence electron look at Group Number and you can find it, Example barium it’s on group 2 it’s means it have 2 valence electrons.
let’s look for nitrogen group 5A that means it have 5 valence eletrons.
hope it’s help.
Let me know if you have any chemistry related questions

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parantesis () or brackets [].

Common compound names.

Examples of molar mass computations: NaCl, Ca(OH)2, K4[Fe(CN)6], CuSO4*5H2O, water, nitric acid, potassium permanganate, ethanol, fructose.

Molar mass calculator also displays common compound name, Hill formula, elemental composition, mass percent composition, atomic percent compositions and allows to convert from weight to number of moles and vice versa.

Computing molecular weight (molecular mass)

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4 years ago
Consider the reaction: A (aq) ⇌ B (aq) at 253 K where the initial concentration of A = 1.00 M and the initial concentration of B
Ugo [173]

Answer:

The maximum amount of work that can be done by this system is -2.71 kJ/mol

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Maximum amount of work denoted change in gibbs free energy (\Delta G) during the reaction.

Equilibrium concentration of B = 0.357 M

So equilibrium concentration of A = (1-0.357) M = 0.643 M

So equilibrium constant at 253 K, K_{eq}= \frac{[B]}{[A]}

[A] and [B] represent equilibrium concentrations

K_{eq}=\frac{0.357}{0.643}=0.555

When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M

So reaction quotient at this situation, Q=\frac{0.133}{0.867}=0.153

We know,  \Delta G=RTln(\frac{Q}{K_{eq}})

where R is gas constant and T is temperature in kelvin

Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and K_{eq} is 0.555

So, \Delta G=8.314\times 253\times ln(\frac{0.153}{0.555})mol/K

                           = -2710 J/mol

                            = -2.71 kJ/mol

4 0
3 years ago
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