All categories

4 years ago

In a 0.737 m solution, a weak acid is 12.5% dissociated. calculate ka of the acid.

Chemistry

1 answer:

r-ruslan [8.4K]4 years ago

8 0

Hello! Let me try to answer this :)

Thanks and please correct if there are any mistakes ^ ^

You might be interested in

A quantity that had just a number

Mama L [17]

Answer:

Explanation:

4 0

3 years ago

A 13-gram rubber stopper is attached to a 0.93-meter

makkiz [27]

<h3>Answer:</h3>

The centripetal acceleration is 26.38 m/s²

<h3>Explanation:</h3>

We are given;

Mass of rubber stopper = 13 g
Length of the string(radius) = 0.93 m
Time for one revolution = 1.18 seconds

We are required to calculate the centripetal acceleration.

To get the centripetal acceleration is given by the formula;

Centripetal acc = V²/r

Where, V is the velocity and r is the radius.

Since time for 1 revolution is 1.18 seconds,

Then, V = 2πr/t, taking π to be 3.142 ( 1 revolution = 2πr)

Therefore;

Velocity = (2 × 3.142 × 0.93 m) ÷ 1.18 sec

= 4.953 m/s

Thus;

Centripetal acceleration = (4.953 m/s)² ÷ 0.93 m

= 26.38 m/s²

Hence, the centripetal acceleration is 26.38 m/s²

6 0

3 years ago

Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t

Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is $1.743\times 10^2g$

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

$\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol$

The chemical equation for the hydrogenation of decene follows:

$C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)$

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = $\frac{1}{1}\times 1.225=1.225mol$ of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

$1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g$

Hence, the mass of decane produced is $1.743\times 10^2g$

5 0

3 years ago

Which scientific discipline belongs in the blue box?

Brums [2.3K]

Answer:

chemistry I think.

Explanation:

I don't need a thanks.

7 0

3 years ago

Read 2 more answers

D. What do all of the molecules in the table have in common?

blsea [12.9K]

Answer:

They all have a certain amount of protons electrons and neutrons.

6 0

3 years ago