Hello!
Firstly, we need to determine the atomic formula of carbon monoxide.
When breaking down the name, we know that there is only one carbon atom since we normally do not add the prefix mono- (one), in the front of the first element. Secondly, there is one oxygen atom since mono = one, and oxide is oxygen. Carbon monoxide is written as: CO.
Now, to find the number of molecules, we will need to use a conversion factor, and also we must know Avogadro's number: <u>6.02 x 10^23 molecules</u>.
To set up the conversion factor, we must change the units from "moles CO" to "molecules CO". To do that, we will begin with the given number, "0.75 moles CO", and multiply that by "6.02 x 10^23 molecules CO over 1 mol CO".
0.75 moles CO x (6.02 x 10^23 molecules CO / 1 mol CO) = 4.52 x 10^23 molecules CO
Therefore, there are about 4.52 x 10^23 molecules CO.
My sister is saying it’s A, but I think it’s C. Only because I had this question in my test before.
Answer:
A table salt molecule is bigger than a salt molecule.
Explanation:
I'm saying this because it's a table salt and salt could be much smaller and table salt could be bigger.
Answer:Graphite has a giant covalent structure in which: each carbon atom is joined to three other carbon atoms by covalent bonds.
Answer:
See explanation
Explanation:
9) If an extra electron is added to the neon atom, then the electronic configuration becomes; 1s2 2s2 2p6 3s1
This last electron has quantum numbers;
n=3, l=0, m=0 and s = +1/2
This is so because the 2s level is already filled so the extra electron must go into the 3s level. The orbital quantum number and the magnetic quantum number for the s orbital is zero.
10) Electron affinity is the energy released when one mole of gaseous atoms accept one mole of gaseous electrons to form one mole of gaseous ions having a negative charge.
In the second period, fluorine has the greatest electron affinity since electron affinity increases across the period. The noble gas, neon has an electron affinity of 0KJ/mol.
11) Ionization energy decreases down the group but increases across the period due to increase in the size of the nuclear charge and decrease in the distance between the nucleus and the outermost electron. Hence, the process; Br+(g) ---->Br2+(g) + e- has the greatest ionization energy. Recall that the second ionization is always higher than the first ionization energy.
12)The order of decreasing metallic character here is K> As> P. Even though As and P belong to the same group, we must note that metallic character increases down the group hence the order written above.
= 8.5 mol H₂SO₄