The correct answer is A because a higher population count always results in the use of more resources (and thus less available in the end). This is why carrying capacities of ecosystems tend to get lower as population counts rise.
Do you have the molecular weight? I’ve never done this type of chemistry before but from researching it the equation is nxAx100/M. n=# of atoms, A=atomic mass, & M=molecule weight. Sorry if this isn’t helpful, if you can give me an example I may be able to help.
Answer:
All atoms of the same element have the same number of protons
Explanation:
All atoms of the same element have the same number of protons. The atoms are formed by protons, neutrons (both located in the nucleus) and electrons located on the outside. The number Z characterizes each element (corresponds to the number of protons located in the nucleus, which coincides with the number of electrons). The number A corresponds to the sum of protons and neutrons of an element (it varies in isotopes, since the number of neutrons varies).
Answer:
6 H⁺ + BrO₃⁻ + 3 Sb³⁺ ⟶ Br⁻ + 3 H₂O + 3 Sb⁵⁺
Explanation:
Step 1: Write the unbalanced reaction
BrO₃⁻ + Sb³⁺ ⟶ Br⁻ + Sb⁵⁺
Step 2: Identify both half-reactions
Reduction: BrO₃⁻ ⟶ Br⁻
Oxidation: Sb³⁺ ⟶ Sb⁵⁺
Step 3: Perform the mass balance, adding H⁺ and H₂O where appropriate
6 H⁺ + BrO₃⁻ ⟶ Br⁻ + 3 H₂O
Sb³⁺ ⟶ Sb⁵⁺
Step 4: Perform the charge balance, adding electrons where appropriate
6 H⁺ + BrO₃⁻ + 6 e⁻ ⟶ Br⁻ + 3 H₂O
Sb³⁺ ⟶ Sb⁵⁺ + 2 e⁻
Step 5: Multiply both half-reactions by numbers that assure that the number of electrons gained and lost is the same
1 × (6 H⁺ + BrO₃⁻ + 6 e⁻ ⟶ Br⁻ + 3 H₂O)
3 × (Sb³⁺ ⟶ Sb⁵⁺ + 2 e⁻)
Step 6: Add both half-reactions and cancel what is repeated in both sides
6 H⁺ + BrO₃⁻ + 3 Sb³⁺ ⟶ Br⁻ + 3 H₂O + 3 Sb⁵⁺
There are 2 compounds in CO2