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agasfer [191]
3 years ago
14

the moon orbits our earth. the opposite would never be true: the earth would never orbit the moon. one reason is due to the forc

e of gravity. the object _________ has a greater gravitaional force and that determines what satelites orbit around it.
Physics
1 answer:
jok3333 [9.3K]3 years ago
4 0

Answer: The moon keeps the same face pointing towards the Earth because its rate of spin is tidally locked so that it is synchronized with its rate of revolution (the time needed to complete one orbit). In other words, the moon rotates exactly once every time it circles the Earth.

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A projectile is fired with a velocity of 22 m/s at an angle of 25°. What is the vertical component of the velocity?
7nadin3 [17]

Answer:

Vertical component of velocity is 9.29 m/s

Explanation:

Given that,

Velocity of projection of a projectile, v = 22 m/s

It is fired at an angle of 22°

The horizontal component of velocity is v cosθ

The vertical component of velocity is v sinθ

So, vertical component is given by :

v_y=v\ sin(25)

v_y=22\ m/s\times\ sin(25)

v_y=9.29\ m/s

Hence, the vertical component of the velocity is 9.29 m/s

3 0
4 years ago
How do i do this??????????
Sliva [168]
Power = I^2 x R
Energy = Power x Time
4 0
3 years ago
A boat traveled upstream 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at
MAVERICK [17]

Answer:

A) 2.5

Explanation:

Extracting vital information from the question;

speed upstream = (v-3)mile/hr, distance traveled = 90 mile, speed downstream = (v+3), time for downstream in hours = t while time for upstream = t + 0.5 hr since the upstream journey is half hour longer.

speed = distance / time = 90 / (t + 0.5)

( v - 3) = 90 / ( t + 0.5)

cross multiply

(v-3) (t + 0.5) = 90 equation (1) for upstream motion

( v+3) = 90 / t

cross multiply

t(v+3) = 90 equation (2) for downstream motion

make v subject of the formula in equation 2

vt + 3t = 90

vt = 90 - 3t

divide both side by t

vt/t = (90 - 3t) / t

v = (90 - 3t) / t

 substitute for t in equation 1

(( 90 - 3t) / t) - 3) (t + 0.5) = 90

solve through finding l.c.m ( lowest common multiple)

(90 - 3t - 3t)/ t (t + 0.5) = 90

(( 90 - 6t ) / t )(t + 0.5) = 90

open the brackets and cross multiply

90t + 45 - 6t² - 3t = 90 t

rearrange  and collect the like terms

- 6t² - 3t + 45 = 90t - 90t

- 6t² - 3t + 45 = 0 multiply both side by -1

6t² + 3t - 45 = 0

divide both side by 3

2t² + t - 15 =  0

factorize the expression by multiplying - 15 by 2t² = - 30t²

find factors of - 30t² that adds to t  = 6t × (-5t)

replace t with (+6t - 5t) in the equation

2t²+ 6t - 5t - 15 = 0

factorize

2t ( t + 3) - 5 ( t + 3) =0

(2t -5)(t + 3) = 0  

2t - 5  = 0 or t + 3 = 0

2t = 5 or t = -3

divide through 2

2t / 2 = 5/ 2 = 2.5 or t = -3 since time cannot be negative

them t = 2..5 seconds

3 0
3 years ago
Please help I really need it​ please
Nana76 [90]
What is the question?
4 0
3 years ago
A loop of wire is at the edge of a region of space containing a uniform magnetic field B⃗ . The plane of the loop is perpendicul
Fantom [35]

QUESTION:

Part A

The induced emf in the loop is measured to be V. What is the magnitude B of the magnetic field that the loop was in?

Part B

For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the figure), what is the rate of change of area c = -\dfrac{dA}{dt}?

Answer:

Part A: B = -\dfrac{V}{c}

Part B: c=-Lv

Explanation:

Part A:

Faraday's law says that the induced voltage is equal to

V =-N \dfrac{d\Phi_B}{dt},

which in our case(because we have only one loop) becomes

V =- \dfrac{d (BA)}{dt},

and since the magnetic field is uniform (not changing),

V =-B \dfrac{dA}{dt}.

Now, we know that \dfrac{dA}{dt} =c;

therefore,

V =-B c

which gives us

\boxed{B = -\dfrac{V}{c} }

Part B:

The area of the loop can be written as

A = Lx,

where x is the instantaneous length of the side along which the loop is moving.

Taking the derivative of both sides we get:

\dfrac{dA}{dt} = -L\dfrac{dx}{dt},

and since v =\dfrac{dx}{dt} we have

c = \dfrac{dA}{dt} = -Lv

\boxed{c=-Lv}

where the negative sign indicates that the area is decreasing.

7 0
4 years ago
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