Answer:
a) t = 2.64s
b) Vf = -28.7m/s
Explanation:
If the balloon is descending, the velocity is -2.3m/s. So the equation to describe the postion of the falling camera is:
Solving for t, we get:
t1 = -3.1s and t2 = 2.64s We discard the negative time and use the positive one.
The velocity of the camera will be:
Vf = Vo - g*t = -2.3 - 10*2.64 = -28.7m/s
<em>Answer</em>
Force = 170 N
<em>Explanation</em>
First find the distance (d) travelled by the bulldozer.
Sin 35 = 15/d
d = 15/(sin 35)
= 26.15m
Now;
work done = force × distance.
4500 J = force × 26.15
dividing both sides by 26.15,
Force = 4500/26.15
= 172.07 N
Answer to two significant figures = 170 N
Answer: Statement 1 is incorrect.
Reason:
Unit of measure of angular distance is not meters.
Explanation:
The term 'angular size' is used to describe the apparent size of the objects in the night sky.
The angular distance is defined as the angle through which an object moves on a circular path. The SI unit is radian.
Other units are revolution (rev) and degrees.
In statement 1, angular distance is measured in meters which is incorrect. In other options, there is no factual mistake so they are correct.
Let's discuss them,
Statement 2:
Here, we are talking about the use of outstretched hand to estimate the angular distances and sizes which is correct.
Statement 3:
This statement talks about the same angular sizes of the sun and the moon, here the term is again used correctly.
Statement 4:
Here, the angular distance is measured in the correct units i.e, degrees so this statement is also correct.
Answer:
Increasing
Explanation:
It’s increasing because your are adding more weight
a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J
b.) K 2 +GmM( r 11− r 21)=6.9×10 7 J
Applying Law of Energy conservation :
K 1+U 1
=K 2+U 2
⇒K 1− r 1GmM
=K 2− r 2 GmM
where M=5.0×10 23kg,r1
=> R=3.0×10 6m and m=10kg
(a) If K 1
=5.0×10 7J and r 2
=4.0×10 6 m, then the above equation leads to
K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J
(b) In this case, we require K 2
=0 and r2
=8.0×10 6m, and solve for K 1:K 1
=K 2 +GmM (r 11− r 21)=6.9×10 7 J
Learn more about Kinetic energy on:
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