Question

If a car accelerates uniformly from rest to 15 meters

Answer 1

Answer:

1.125m/s^2

Explanation:

Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically

v^2= u^2+2as

Where a,v,u and s are the acceleration, final velocity, initial velocity and distance respectively.

a = ?

u = 0m/s

v = 15m/s

s = 100m

Substituting the values into the formula above

v^2= u^2+2as

15^2=0^2+2×a×100

225= 0+200a

225= 200a

Divide both sides by 200

225/200 = 200a/200

a= 1.125m/s^2

Hence the acceleration of the car is 1.125m/s^2.

Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s

Answer 2

Answer:

1.125 m/s²

Explanation:

Applying Newton's equation of motion,

v² = u²+2as

Where v = final velocity, u = initial velocity, a = acceleration, s = distance.

Note: u = 0 m/s ( from rest)

make a the subject of the equation above.

a = v²/2s................ Equation 2

Given: v = 15 m/s². s =  100 m

Substitute into equation 2

a = 15²/(2×100)

a = 225/200

a = 1.125 m/s²