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hammer [34]
3 years ago
9

Suppose you wanted to change the fundamental frequency of an oscillating string. What are three parameters that you could alter

and how would these alter the oscillation frequency?
Physics
1 answer:
Keith_Richards [23]3 years ago
8 0

Answer:

Linear density, Length, and tension in the string

Explanation:

The fundamental frequency of an oscillating string is given by:

f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}

where

L is the length of the string

T is the tension in the string

\mu is the linear density of the string, which can also be rewritten as

\mu = \frac{m}{L}

where m is the mass of the string.

Therefore, we can say that in order to change the fundamental frequency of the string, we can change either its lenght, or its tension or its linear density.

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As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level. This is what meteorologists and mountaineers mean by "thin air." Thin air exerts less pressure than air at a lower altitude

4 0
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the density of gas is 1.775kg/m^3 at 27 degree celcius and pressure of 10^-5n/m^2. if the specific heat capacity at constant pre
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76.52

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3 years ago
150kg object takes 1.5minutes to travel 2,500 meter straight path it begins the trip traveling 120m/s and decelerates to a veloc
Free_Kalibri [48]
<h2>Answer:</h2>

Acceleration= -1.11 m/sec²


<h2>Explanation:</h2>

Date Given to us is

Mass = 150 kg

Time = 1.5 minutes = 90 seconds

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Final Velocity = 20 m/s

Acceleration = ?

<u>Solution:</u>

By using First Equation of motion

Vf = Vi + at

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Subtracting 120 on both sides

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So the acceleration is -1.11 m/s²

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